CODEWITHSUNDEEP
phpjquerygetjson
Satch3000
Satch3000

Reputation: 49384

JQuery getJSON / PHP returning data and displaying the data

I have a login using getJSON and PHP.

Right now all it does it checks if the user and password is valid but if it is I want to pass further information to the client.

Right now on the server side I do this:

if ($result->num_rows) {            
    echo '{"response":{"error": "1"}}';         
} else {
    echo '{"response":{"error": "0"}}';
}

and on the client side I have this:

if (json.response.error == "1") {
    data = "Welcome "+username;
    alert(data);
} else {
    // Login fail
    data = "Wrong Username/Password";
    alert(data);
}

So basically it's just checking.

How can I pass some more information from the server to the client?

Update: I've changed the code to this but it's now not working:

Server:

if ($result->num_rows) {

//echo '{"response":{"error": "1"}}';
$data = array(
'response'     => array(
'error'    => 1,
),
'someData'     => 'data';
);
print json_encode($data);
}

Client:

$.getJSON("server.php", {username:username,password:password},function(data)
{

alert('hello');
var json = JSON.parse(data);
alert(json.responseCode);


});

Upvotes: 0

Views: 617

Answers (2)

BMN
BMN

Reputation: 8508

On the server side, You can create an array containing all the data you need and then send it from the server to the client using json_encode() :

$data = array(
    'response'     => array(
        'error'    => 1,
    ),
    'someData'     => 'data',
    ...
);
print json_encode($data);

And on the client side :

var json = JSON.parse(data);
alert(json.response.error);

Hope it helps !

Upvotes: 2

Jai
Jai

Reputation: 74738

You have to use jQuery.parseJSON(json) where json here is a well formed json string.

From the documentation:

It takes a well-formed JSON string and returns the resulting JavaScript object.

So you have to parse the string first to a javascript object.

var json = $.parseJSON(data); // data is the json string
if (json.response.error == "1") {
   data = "Welcome "+username;
   alert(data);
} else {
   // Login fail
   data = "Wrong Username/Password";
   alert(data);
}

Upvotes: 1

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