Reputation: 2975
I saw redefine function here using macro in c. So I am interesting is it possible to redefine main function?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char **argv)
{
printf("Original main function\n");
return 0;
}
int _main(int argc, char **argv)
{
printf("New Original main function\n");
return main(argc, argv);
}
#ifdef DEBUG
#define main(argc, argv) _main(argc, argv)
#endif
Code compiled with out any problem but I am getting:
Original main function
So I am wondering why it does not work? When I use same techniques for malloc
and free
functions it works perfect. So what is wrong?
Why I want to do something like this? I want to do some code before main
function will be executed. Is it possible in this way? if not is there are some other way?
P.S.: Sorry I did not mention in question. I am using gcc in Ubuntu OS. If you are down voting please give a reason in comments. You comments is very useful to my further development.
Upvotes: 0
Views: 3283
Reputation: 3004
If your question is really: "can i execute code before main?" Then the answer is an emphatic YES.
Since you are using GCC, you can use function attributes (http://gcc.gnu.org/onlinedocs/gcc/Function-Attributes.html) to mark a function as a constructor.
void pre_main_function (void) __attribute__ ((constructor));
A useful example can be found at http://www.geeksforgeeks.org/functions-that-are-executed-before-and-after-main-in-c/
EDIT
The following syntax can also be used:
__attribute__ (( constructor(n) ))
where n
specifies the priority, allowing you to mark multiple functions to be executed before main whilst giving you control over the execution order ( the lower the value of n, the earlier the function is executed.
Upvotes: 1
Reputation: 5163
If you want to change entry point of your program, you don't need play with defines. You can use linker's -e
option for that:
gcc -Wl,-e,__main ...
Please note extra underscore. Depending on some options, the symbol name can be different.
Upvotes: 2
Reputation: 5041
Your #define does not change the main function at all - it is a macro preprocessor.
The only effect of your #define will be to change the call to main in _main into a recursive call to _main(). But since _main is not called, this is dead code. This is what your code looks like after the preprocessor has run...
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char **argv)
{
printf("Original main function\n");
return 0;
}
int _main(int argc, char **argv)
{
printf("New Original main function\n");
return _main(argc, argv); /* recursive call due to macro replace */
}
This then leads to the next question - which is why redefine main at all? If you want some entirely different code to run on debug simply declare main as
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char **argv)
{
#ifdef DEBUG
return debugApp( argc, argv);
#else
return productionApp( argc, argv);
#endif
}
N.B Just because you can do something doesn't mean you should do it. :-)
Upvotes: 1