CODEWITHSUNDEEP
pythonemailtextpop3poplib
mplewis
mplewis

Reputation: 464

Python: Retrieving only POP3 message text, no headers

I'm trying to make a Python program that retrieves only the body text of an email without passing headers or any other parameters. I'm not sure how to go about this.

The goal is to be able to send basic commands to a program via message text.

What I have now is this:

import poplib

host = "pop.gmail.com"
mail = poplib.POP3_SSL(host)
print mail.getwelcome()
print mail.user("user")
print mail.pass_("pass")
print mail.stat()
print mail.list()
print ""

if mail.stat()[1] > 0:
    print "You have new mail."
else:
    print "No new mail."

print ""

numMessages = len(mail.list()[1])
for i in range(numMessages):
    for j in mail.retr(i+1)[1]:
        print j

mail.quit()
input("Press any key to continue.")

Which is all fine, except when "print J" is executed it prints the entire message, including headers. I just want to extract the body text without any additional garbage.

Can anyone help? Thanks!

Upvotes: 6

Views: 14774

Answers (3)

Chaos Manor
Chaos Manor

Reputation: 1220

I would use email module to get the body of email message with get_payload() method which skips header info.

I added few lines to your code (they are marked with # new statement at the end of line)

import poplib
import email # new statement

host = "pop.gmail.com"
mail = poplib.POP3_SSL(host)
print mail.getwelcome()
print mail.user("user")
print mail.pass_("pass")
print mail.stat()
print mail.list()
print ""

if mail.stat()[1] > 0:
    print "You have new mail."
else:
    print "No new mail."

print ""

numMessages = len(mail.list()[1])
for i in range(numMessages):
    for j in mail.retr(i+1)[1]:
        #print j
        msg = email.message_from_string(j) # new statement
        print(msg.get_payload()) # new statement

mail.quit()
input("Press any key to continue.")

Upvotes: 5

PaulMcG
PaulMcG

Reputation: 63709

This is a fragment of code from my own POP3 reader:

        response, lines, bytes = pop.retr(m)

        # remove trailing blank lines from message
        while lines[-1]=="": 
            del lines[-1]

        try:
            endOfHeader = lines.index('')
            header = lines[:endOfHeader]
            body = lines[endOfHeader+1:]
        except ValueError:
            header = lines
            body = []

This keys off the first empty line in the list of all lines as the end of the header info. Then just list slice from there to the end for the message body.

Upvotes: 4

ebo
ebo

Reputation: 9215

You can parse eMails using the email module.

Upvotes: 2

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