CODEWITHSUNDEEP
phphtmlforms
JeremyThePHPNoob
JeremyThePHPNoob

Reputation: 17

add multiple items to a database in one form

I've got an internal site I'm developing for work. I'm by no means a web developer but know enough to get some basic functionality done. I've got a form working fine for inserting data. I'm trying to figure out this one last piece, though.

The page is designed to add jobs to our site. Each position has assigned responsibilities. The easiest way to make this work (in my brain) is to create a table for responsibilities that has a responsibilityID, PositionID, and then the responsibility. I want a way to kind of bulk add these responsibilities when completing the form for the new position. Something similar to how you add new fields when using the MySQL workbench - where you can just click on the next row and it'll add that field. That would work great.

I'm not sure what to even search for to accomplish this other than adding multiple items - which hasn't turned up what I'm looking for.

Thanks in advance!

Upvotes: 0

Views: 1568

Answers (3)

Tyson of the Northwest
Tyson of the Northwest

Reputation: 2121

If you have a form that allows you to submit multiple responsibilities simultaneously then I would use PDO. Remember PDO is your friend, and always sanitize your inputs before inserting them. Here is them most basic version, You probably want to replace the inputs with dropdowns or texteareas.

table

responsibilityID|PositionID|responsibility

The responsibilityID should be PK and auto-increment

html

<form>
  <div>
    <h1>job</h1>
    <label>PositionID</label><input name='jobs[][positionID]' />
    <label>responsability</label><input name='jobs[][responsibility]' />
  </div>
  <div>
    <h1>job</h1>
    <label>PositionID</label><input name='jobs[][positionID]' />
    <label>responsability</label><input name='jobs[][responsibility]' />
  </div>
  <div>
    <h1>job</h1>
    <label>PositionID</label><input name='jobs[][positionID]' />
    <label>responsability</label><input name='jobs[][responsibility]' />
  </div>
  <div>
    <h1>job</h1>
    <label>PositionID</label><input name='jobs[][positionID]' />
    <label>responsability</label><input name='jobs[][responsibility]' />
  </div>
  <input type='submit' />
</form>

Basic

Create an insert statement then loop through your jobs binding each value to the statement and executing them.

$insert_sql = "INSERT INTO responsibilities (`PositionID`, `responsibility`) VALUES (:PositionID, :responsibility);";
$stmt = PDO::Prepare($insert_sql)
foreach ($jobs as $job){
  //add some input testing before you execute to make sure you are not inserting bad values
  $stmt->bindValue(":positionID", $job['positionID'], PDO::PARAM_INT);
  $stmt->bindValue(":responsibility", $job['responsibility'], PDO::PARAM_STR);
  $stmt->execute();
}

The :fieldname in the query tells PDO what needs to be replaced with the bind functions, then the bindValue/bindParam functions tells what to insert where into the query and properly escapes the value so you can insert it. Older sql functions allowed for unescaped or improperly escaped values and you got the little bobby tables problem. PDO protects you from some of the worst injection attacks, but you should probably make sure that positionID points to a real position or that responsibility doesn't have weird java-script exploit code in it.

Fancy

Create an insert statement, bind params, then foreach loop through your responsibilities, checking/sanitizing the input (never trust form data) then executing the statement. Every time you loop the bound parameter will point at the new job.

$insert_sql = "INSERT INTO responsibilities (`PositionID`, `responsibility`) VALUES (:PositionID, :responsibility);";
$job = array('positionID'=>NULL, 'responsibility'->NULL);
$stmt = PDO::Prepare($insert_sql)
$stmt->bindParam(":positionID", $job['positionID'], PDO::PARAM_INT);
$stmt->bindParam(":responsibility", $job['responsibility'], PDO::PARAM_STR);
foreach ($jobs as $job){
  //add some input testing before you execute to make sure you are not inserting bad values
  $stmt->execute();
}

Upvotes: 1

NguyenNgocPhuong
NguyenNgocPhuong

Reputation: 437

with the inputs you want to have multi values, use the name attribute like responsibilities[], and then insert serialized data to the database

Upvotes: 0

13ruce1337
13ruce1337

Reputation: 733

Most times people here like to see what you've tried.

This question was asked here.

example MySQL statement:

INSERT INTO tbl_name (a,b,c) VALUES(1,2,3),(4,5,6),(7,8,9);

You can replace the values with PHP variables if needed. Just make sure if they are strings, they are in 'quotes'.

Upvotes: 2

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