TypeError message in Pythons PIL (v2.6): integer expected, got float

Question

first time I'm in the forum. Hope I'm specific enough. Using ImageChops inside PIL, I'm trying to multiply two images (both mode="L") but I always get the same error message. I've looked everywhere but couldn't find anything useful. I'd greatly appreciate any helpful ideas! The relevant part of the code is attached.

    def point(self, f, searchImage, technique): # technique - inpaint or bicubic

    dimx, dimy = searchImage.size

    reader = csv.reader(f)
    for line in reader: #f.readlines():
        coord = line
        print coord
        if searchImage.size[0] > float(coord[0])+95.5 and searchImage.size[1]\
           > float(coord[1])+95.5: 
            box = (float(coord[0])-93.5,float(coord[1])-93.5,\
                   float(coord[0])+95.5,float(coord[1])+95.5)     # left upper right
        elif searchImage.size[0] < float(coord[0])+95.5 and searchImage.size[1]\
             > float(coord[1])+95.5:
            box = (float(coord[0])-93.5,float(coord[1])-93.5,\
                   searchImage.size[0]-0.5,float(coord[1])+95.5)  # size of box
            # depends on pixel size. A pixel size of 14 micrometer results in a
            # cross size of 189 pixels
        else:
            box = (float(coord[0])-93.5,float(coord[1])-93.5,\
                   float(coord[0])+95.5,searchImage.size[1]-0.5)

        box = (math.floor(box[0]), math.floor(box[1]), math.floor(box[2]),\
               math.floor(box[3])) 

        searchCrop = searchImage.crop(box)

        c_x = int(float(coord[1])) 
        c_y = int(float(coord[0])) 
        abst_y = c_x - int(math.floor(box[1])) - 1 # x shift

        center = num.asarray(searchImage)[c_x,c_y]
        if center == 0:
            center = center + 0.00001 # to avoid division by zero
        val = [num.asarray(searchImage)[c_x-1,c_y+1], num.asarray(searchImage)\
               [c_x-1,c_y-1], num.asarray(searchImage)[c_x+1,c_y-1], \
               num.asarray(searchImage)[c_x+1,c_y+1]] # ERDAS upper right,
        # upper left, lower left, lower right

        val_dict = {0:1,1:-1,2:-1,3:1}
        flag = val_dict[val.index(min(val))]
        if float(min(val))/center > 2. or min(val) > 100:
            flag = 0

        newima = num.zeros( (searchCrop.size[1], searchCrop.size[0]),\
                            dtype = "float")

        Ayo = num.array(int(searchCrop.size[0])*[255]) 
        Ay = num.array((abst_y + flag)*[255] + 3*[0] + ((int(searchCrop.size[0]\
                                                             )-3-abst_y)-flag)*[255]) 
        Ax = num.array(int(searchCrop.size[0])*[0])  
        Kx = num.array(3*[Ayo] + ((int(searchCrop.size[1])-9)/2+flag)*[Ay] + 3*[Ax] \
                       + ((int(searchCrop.size[1])-9)/2-flag)*[Ay] + 3*[Ayo])   

        Kxlist = list(itertools.chain(*Kx))

        i=0
        for y in range(int(searchCrop.size[1])): 
            for x in range(int(searchCrop.size[0])):        
                newima[y,x] = Kxlist[i+y+x]
            i=i+x

        kernel = Image.fromarray(newima)
        kernel = kernel.convert(mode="L")

        # -----
        modified = ImageChops.multiply(searchCrop,kernel)   # Results in an image 
        # where the pixels along the cross axes will get a value of 0
        # ---

The error message is the following:

File "D:\GIS_dbase\Data\hma_cci\hexagon\KH9_Python\interpolate_cross.py", line 58, in 
 crossInterpolation filledImage = self.p_model.point(f, searchImage, method) 
File "D:\GIS_dbase\Data\hma_cci\hexagon\KH9_Python\interpolate_cross.py", line 207, in 
 point modified = ImageChops.multiply(searchCrop,kernel)   # Results in an image where 
 the pixels along the cross axes will get a value of 0
File "C:\Python27\lib\site-packages\PIL\ImageChops.py", line 119, in multiply
 image1.load()
File "C:\Python27\lib\site-packages\PIL\Image.py", line 1730, in load
 self.im = self.im.crop(self.__crop)
TypeError: integer argument expected, got float

TypeError message in Pythons PIL (v2.6): integer expected, got float

Answers (1)

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