Reputation: 85
So I have this code here:
create or replace FUNCTION calc_length(
START_TIME IN number,
FINISH_TIME IN number
) RETURN NUMBER IS
BEGIN
RETURN ( (FINISH_TIME - START_TIME ) ;
END
And I want to show the result in the format as H:mm
I tried TO_CHAR
function but it accepts a strict preset formats.
Upvotes: 1
Views: 438
Reputation: 5792
Few examples - copy, paste to see the oputput:
SELECT trunc(mydate / 3600) hr
, trunc(mod(mydate, 3600) / 60) mnt
, trunc(mod(mydate, 3600) / 60 /60) sec
FROM
(
SELECT (to_date('01/02/2013 23:00:00', 'mm/dd/yyyy hh24:mi:ss') -
to_date('01/01/2013 07:00:00', 'mm/dd/yyyy hh24:mi:ss')) * 86400 mydate
FROM dual
)
/
Select hh, mi, ss From
(
Select EXTRACT(hour From Cast(SYSDATE as timestamp)) hh,
EXTRACT(minute From Cast(SYSDATE as timestamp)) mi,
EXTRACT(second From Cast(SYSDATE as timestamp)) ss
From dual
)
/
Select start_date, end_date, time_diff,
EXTRACT(DAY FROM time_diff) days,
EXTRACT(HOUR FROM time_diff) hours,
EXTRACT(MINUTE FROM time_diff) minutes,
EXTRACT(SECOND FROM time_diff) seconds
From
(
Select start_date, end_date, end_date - start_date time_diff
From
(
Select CAST(to_date('21/02/2012 06:10:53 am', 'dd/mm/yyyy hh:mi:ss am') AS TIMESTAMP) end_date
, CAST(to_date('21/02/2012 12:05:00 am', 'dd/mm/yyyy hh:mi:ss am') AS TIMESTAMP) start_date
From dual
))
/
Upvotes: 1