Reputation: 17482
I am new to Scala and but very old to Java and had some understanding working with FP languages like "Haskell".
Here I am wondering how to implement this using Scala. There is a list of elements in an array all of them are strings and I just want to know if there is a way I can do this in Scala in a FP way. Here is my current version which works...
def checkLength(vals: Array[String]): Boolean = {
var len = -1
for(x <- conts){
if(len < 0)
len = x.length()
else{
if (x.length() != len)
return false
else
len = x.length()
}
}
return true;
}
And I am pretty sure there is a better way of doing this in Scala/FP...
Upvotes: 11
Views: 10431
Reputation: 13520
list.groupBy{_.length}.size == 1
You convert the list into a map of groups of equal length strings. If all the strings have the same length, then the map will hold only one such group.
The nice thing with this solution is that you don't need to know anything about the length of the strings, and don't need to comapre them to, say, the first string. It works well on an empty string, in which case it returns false (if that's what you want..)
Upvotes: 2
Reputation: 18177
Just my €0.02
def allElementsEval[T, U](f: T => U)(xs: Iterable[T]) =
if (xs.isEmpty) true
else {
val first = f(xs.head)
xs forall { f(_) == first }
}
This works with any Iterable
, evaluates f the minimum number of times possible, and while the block can't be curried, the type inferencer can infer the block parameter type.
"allElementsEval" should "return true for an empty Iterable" in {
allElementsEval(List[String]()){ x => x.size } should be (true)
}
it should "eval the function at each item" in {
allElementsEval(List("aa", "bb", "cc")) { x => x.size } should be (true)
allElementsEval(List("aa", "bb", "ccc")) { x => x.size } should be (false)
}
it should "work on Vector and Array as well" in {
allElementsEval(Vector("aa", "bb", "cc")) { x => x.size } should be (true)
allElementsEval(Vector("aa", "bb", "ccc")) { x => x.size } should be (false)
allElementsEval(Array("aa", "bb", "cc")) { x => x.size } should be (true)
allElementsEval(Array("aa", "bb", "ccc")) { x => x.size } should be (false)
}
It's just a shame that head :: tail
pattern matching fails so insidiously for Iterables.
Upvotes: 0
Reputation: 297295
Since everyone seems to be so creative, I'll be creative too. :-)
def checkLength(vals: Array[String]): Boolean = vals.map(_.length).removeDuplicates.size <= 1
Mind you, removeDuplicates
will likely be named distinct
on Scala 2.8.
Upvotes: 7
Reputation: 4565
Here's another approach:
def check(list:List[String]) = list.foldLeft(true)(_ && list.head.length == _.length)
Upvotes: 1
Reputation: 167921
If you know that your lists are always non-empty, a straight forall works well. If you don't, it's easy to add that in:
list match {
case x :: rest => rest forall (_.size == x.size)
case _ => true
}
Now lists of length zero return true instead of throwing exceptions.
Upvotes: 2
Reputation: 370445
list.forall( str => str.size == list(0).size )
Edit: Here's a definition that's as general as possilbe and also allows to check whether a property other than length is the same for all elements:
def allElementsTheSame[T,U](f: T => U)(list: Seq[T]) = {
val first: Option[U] = list.headOption.map( f(_) )
list.forall( f(_) == first.get ) //safe to use get here!
}
type HasSize = { val size: Int }
val checkLength = allElementsTheSame((x: HasSize) => x.size)_
checkLength(Array( "123", "456") )
checkLength(List( List(1,2), List(3,4) ))
Upvotes: 21
Reputation: 49228
Tip: Use forall
to determine whether all elements in the collection do satisfy a certain predicate (e.g. equality of length).
Upvotes: 3