CODEWITHSUNDEEP
javascriptjquery
Kid Diamond
Kid Diamond

Reputation: 2301

Passing function parameters on to fadeOut callback

This function accepts up to three parameters. I want to be able to pass those parameters on to the callback function so that I am able to check the arguments there in my if statement.

I checked with console log if there are any parameters present in the callback, and there weren't any.

function foobar(x, y, z) {
    $("div").fadeOut(300, function() {
        if(arguments.length == 1) {
            //nothing
        } else if(arguments.length == 2) {
            $("div").html(x + y).fadeIn(300);
        } else if(arguments.length == 3) {
            $("div").html(x + y + z).fadeIn(300);
        }
    });
}

Upvotes: 0

Views: 420

Answers (1)

hsz
hsz

Reputation: 152266

arguments refers to the nearest function, so here it is a fadeOut callback. Assign foobar function's arguments to the new variable:

function foobar(x, y, z) {
    var foobarArguments = arguments;

    $("div").fadeOut(300, function() {
        if(foobarArguments.length == 1) {
            //nothing
        } else if(foobarArguments.length == 2) {
            $("div").html(x + y).fadeIn(300);
        } else if(foobarArguments.length == 3) {
            $("div").html(x + y + z).fadeIn(300);
        }
    });
}

Upvotes: 1

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