CODEWITHSUNDEEP
c
Andrew
Andrew

Reputation: 49

C programming - Output result in decimals

At the momemt, i'm learning the C and the basics of the language, but I have a problem with my code. When I multiply two numbers, I cant get the decimals, even I float the numbers I enter.

My code:

int main()
{
    double result_met, km;

    result_met = km = 0.0f;

    /*Display text*/
    printf("Enter values of the distance between the two cities in km's\n");
    scanf_s("%d", &km);

    /*Formular for a simple km conversion*/
    result_met = km * 1000.0f;

    /*Result print*/
    printf("Meter:%d", result_met);

    printf("\nWaiting for a character to be pressed from the keyboard to exit.\n");

    getch();

    return 0;
}

Upvotes: 0

Views: 132

Answers (2)

Senua
Senua

Reputation: 586

The format specifier for double is %lf, not %d You may as well use a float instead of a double, it saves memory (which is important when you begin to write big programs), then you must use the format specifier %f (the "l" in %lf is for "long", because a double is a long float)

When treating decimals, you want to print only a few decimals on the screen (to avoid the printing of a "2.50000001"), then you can use the format specifier %.3f if you want 3 and only 3 digits printed (3 can be any integer).

for example, the following code :

printf("%.2f\n",3.1415);

has the following output :

3.14

the printf function has many different format specifier, that can be very useful. Go see the cpluplus.com reference if you want to learn more about it

Upvotes: 1

Sadique
Sadique

Reputation: 22841

The format specifiers are incorrect - it should be %lf - %d is for int.

scanf_s("%lf", &km);

/*Formular for a simple km conversion*/
result_met = km * 1000.0f;

/*Result print*/
printf("Meter:%lf", result_met);

Format string specifications

Upvotes: 2

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