CODEWITHSUNDEEP
javaregex
user1413969
user1413969

Reputation: 1291

Regex replaceAll on a string

Lets assume I have a string:

asdf/dfa/fds?adsf

I want to be able to get the string: asdf?adsf

So essentially I want to parse out everything from the first '/' to the '?'.

I tried experimenting with it (see example below) but I couldn't get it to work: 

s = s.replaceAll("\\/([?]*)", "");

Upvotes: 2

Views: 62

Answers (3)

Paul Draper
Paul Draper

Reputation: 83225

You should change it to this:

s = s.replaceAll("/.*(?=\\?)", "");

(?=\\?) is a look-ahead that means "the next character is a literal ?". (FYI, unescaped, ? has special meaning in a regex.)

However, you did not mention what should happen if there are multiple ?. The regex above will match until the last one.

If you want to match until the first,

s = s.replaceAll("/.*?(?=\\?)", "");

The extra ? causes the repeated match to be "reluctant".

Upvotes: 2

Pshemo
Pshemo

Reputation: 124215

This should do the trick

replaceAll("/[^?]*", "")

/[^?]* will match first / and all non-? characters after it.

Upvotes: 1

Evgeniy Dorofeev
Evgeniy Dorofeev

Reputation: 135992

try this

String s = "asdf/dfa/fds?adsf".replaceAll("/.*(?=\\?)", "");

Upvotes: 1

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