CODEWITHSUNDEEP
routessammy.js
Salvador Dali
Salvador Dali

Reputation: 222621

How can I execute a particular function on every route except one in sammy.js

I have few routes in my application:

Sammy(function() {
    this.get('#!foo', function(){
        ...
    });

    this.get('#!bar', function(){
        ...
    });

    ... and so on...

    this.get('#!special', function(){
        ...
    })
}).run();

And I have a function initialize(); which has no connection to sammy if I hit any of the routes except of #!special. Of course I can copy it each of my routes except the special (which will work, but will be kind of stupid). Is there a way to achieve this?

P.S. or if you do not know how to do this, is there a way to run the function on each route hit?

Upvotes: 3

Views: 719

Answers (1)

rockerest
rockerest

Reputation: 10508

Perhaps Sammy's .before method would work for you?

Here's some sample (untested) code that could do what you want: 

this.before({except: {path: '#!special'}}, function() {
    initialize();
});

The .before() method basically allows you to do some callback before every route, but also allows you to filter out certain routes (or do the opposite and whitelist certain routes).

Upvotes: 2

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