CODEWITHSUNDEEP
phpregexpreg-match-all
Th3Nic3Guy
Th3Nic3Guy

Reputation: 1979

Preg_match_all behaving wierd

I am new to PHP and I have the below code and I basically wish to find all keywords enclosed between

'<#' and '#>'

sample code:

<?php

$subject = "askdbvbaldjbvasdblasdbvl<#2134#>cbkdbskbkabdvb<#213aca4#>";
$pattern = "/(?<=\<\#)(.*?)(?=\#\>)/";
preg_match_all($pattern, $subject, $matches);
echo '<pre>',print_r($matches,true),'</pre>';

?>

now i am expecting a value array like:

Array
(
    [0] => Array
        (
            [0] => 2134
            [1] => 213aca4
        )
)

But i am getting and output like:

Array
(
    [0] => Array
        (
            [0] => 2134
            [1] => 213aca4
        )

    [1] => Array
        (
            [0] => 2134
            [1] => 213aca4
        )

)

can any one tell me why am i getting the second array and how can i get rid of that..

Upvotes: 0

Views: 34

Answers (1)

Jerry
Jerry

Reputation: 71538

The second array contains the sub-match, or matched group, because you're using a capture group.

Simply remove the parens in your regex:

$pattern = "/(?<=\<\#).*?(?=\#\>)/";

Also, you should be able to use this regex without some escapes:

$pattern = "/(?<=<#).*?(?=#>)/";

Upvotes: 3

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