Reputation: 131
Iam reading and writing an image file in java.the file can be of any type so i used buffered reader and writer while writing image its not written properly.The image get scattered.
BufferedReader bufferedReader = null;
BufferedOutputStream bufferedWriter = null;
if(!(dto.getInputStream() == null)){
try {
bufferedReader = new BufferedReader(new InputStreamReader(dto.getInputStream()));
FileOutputStream writer = new FileOutputStream(new File(WEBINFLocation.getWebInfPath()+ConstantIFC.RESOURCEPATH+dto.getFileName()+dto.getDocumentCode()+"_"+dto.getVersion()+1+"."+dto.getFormatName()));
bufferedWriter = new BufferedOutputStream(writer);
int value;
while((value = bufferedReader.read()) != -1){
bufferedWriter.write(value);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
try {
if (bufferedReader != null) {
bufferedReader.close();
}
if (bufferedWriter != null) {
bufferedWriter.close();
}
dto.getInputStream().close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Upvotes: 1
Views: 1510
Reputation: 1499790
This is the problem:
bufferedReader = new BufferedReader(new InputStreamReader(dto.getInputStream()));
You're using an InputStreamReader
, which means it's reading the binary data as text. Don't do that. Your OutputStream
is fine, it's your input handling which is broken.
You should just use InputStream
, or possibly BufferedInputStream
, ideally reading blocks of data at a time instead of a single byte:
byte[] buffer = new byte[8192]; // Try to read 8K at a time
int bytesRead;
while ((bytesRead = input.read(buffer)) > 0) {
output.write(buffer, 0, bytesRead);
}
There are various libraries which help to do this for you, e.g. with Guava you can use BytesStreams.copy
.
Also note that if you're just Java 7, your code can be much simpler using a try-with-resources statement to perform all the closing for you. For example:
try (InputStream input = dto.getInputStream();
OutputStream output = Files.newOutputStream(...)) {
BytesStreams.copy(input, output);
}
Use the Path
API to specify the path to your file - I'd suggest using a call to String.format
instead of all that concatenation, too.
Upvotes: 5