CODEWITHSUNDEEP
phpfloating-point
user1856596
user1856596

Reputation: 7233

Comparing a number to a floating point number?

This is my code:

$number = 99.99;
$randomNumber = rand(1, 100);

if($randomNumber > $number) {
    // ....
}

Could it be that comparing those numbers, the decimal part gets cut off from the 99.99? It seems that its comparing $randomNumber with 99. Could that be and if yes, how can I compare to 99.99?

Thanks!

Upvotes: 1

Views: 90

Answers (3)

Swann
Swann

Reputation: 2473

I would personally try to do something like this 

$number = 99.99
$randomNumber = rand(1, 10000);
if ($randomNumber > number * 100)
{
    // ....
}

It could do the trick.

Upvotes: 0

Henrique Barcelos
Henrique Barcelos

Reputation: 7900

The problem is that rand returns an int, then PHP will convert $number to an int to make the comparison.

What you should really do is simply cast it's value to float:

$number = 99.99;
$randomNumber = (float) rand(1, 100);

if($randomNumber > $number) {
    // ....
}

This solves the problem and you don't need any magic trick.

Upvotes: 1

Dinesh
Dinesh

Reputation: 4110

just explode it:

$number = 99.99;
$new_num=explode('.',$number)
echo $new_num[0];

//output 99

now you can compare it

Upvotes: 0

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