CODEWITHSUNDEEP
xsltxslt-2.0
atif
atif

Reputation: 1147

getting all child nodes of element

I have an xml file on which I am applying transformation to a specific element and then try to get the text() of all the child nodes ignoring same node 

<xml>
    <xrefline>
              <query>eligible individual</query>
              in respect of a qualified dependant at any time means a person who at that time   
              <quote>
              <para> 
               <n>(a)</n> 
              <parap>resides with the qualified dependant,</parap>
             </para> 
              </quote>
       </xrefline>
     </xml>

My xslt template looks like this and I want to extract all the text() and preserve the query element

<xsl:template match="query" >
<xsl:apply-templates select="../text()|../node()[self::query]|../node()[not(self::query)]/text()" ></xsl:apply-templates>
</xsl:template>

My desire output should be like this 

     <xml>
         <xrefline>
              <query>eligible individual</query>
              in respect of a qualified dependant at any time means a person who at that time (a) resides with the qualified dependant,
         </xrefline>
     </xml>

I have to work it around the template match="query" and then go back to get the desire result. With my above xslt I am getting text which is out side the element quote but not the text of sub childs of quote element... any help or hint will be really helpful.

Upvotes: 2

Views: 1621

Answers (1)

Martin Honnen
Martin Honnen

Reputation: 167736

I would write two templates:

<xsl:template match="@* | node()">
  <xsl:copy>
    <xsl:apply-templates select="@* , node()"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="xrefline//*[not(self::query)]">
  <xsl:apply-templates/>
</xsl:template>

see http://xsltransform.net/948Fn5h.

Upvotes: 3

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