Reputation: 3303
I just started going over Prolog about an hour ago and have already stumbled into a slight problem I am unsure about. I am writing a predicate (or function?) that takes a list and returns the min and max values. Right now, I am just looking at one of the special cases when the list has 1 item. For example, if you query minmax([5], X, Y). I want the predicate to return X=5 Y=5. I have this code:
minmax([X], X, X).
but it is returning X = Y, Y = 5. I know it is a true statement and trivial, but is there a way I can return X=5,Y=5 ???
Upvotes: 0
Views: 672
Reputation: 74177
It is returning what you think it is. X is 5 as is Y. The values are unified and so the interpreter shows the message X=Y, Y=5.
You need to get out the Prolog textbook and read up on unification of terms.
You could just as easily say
foo(A,B) :- A = 5 , B is (A+A)/2 .
and query it:
?- foo(X,Y).
and get the same result. In the Prolog universe, there is only ever a single instance of the integer 5
.
Upvotes: 2
Reputation: 363487
X=Y, Y=5
means that X
and Y
are now both equal to 5
. It's just a different way of saying that; you really shouldn't care. If you print both values, you'll just get 5
:
?- [user].
|: print_stuff :-
|: X = Y,
|: Y = 5,
|: write('X = '), writeln(X),
|: write('Y = '), writeln(Y).
|: % user://1 compiled 0.02 sec, 2 clauses
true.
?- print_stuff.
X = 5
Y = 5
true.
Upvotes: 1