CODEWITHSUNDEEP
rrankingranking-functions
Mittenchops
Mittenchops

Reputation: 19734

Variable rank that doesn't skip places in R

I have a vector that looks something like this:

> vec
[1]  1  1  2  5 10

I'm trying to convert this to a form of non-olympic ranking where ties are still ties, but the ranks are guaranteed 1 apart, even when there are multiple ties above it, so:

> f(vec)
[1]  1  1  2  3  4

Rather than:

> rank(vec,ties.method="min")
[1] 1 1 3 4 5

Is there function that does this already in R? I know I could convert the values to factors then rank the factors, but that seems a bit circuitous. (If not a function, is there a name for this kind of ranking?)

(Fun: I hadn't noticed this before, but it looks like rank is idempotent, which is kinda cool:

> rank(vec,ties.method="min")
[1] 1 1 3 4 5
> rank(rank(vec,ties.method="min"),ties.method="min")
[1] 1 1 3 4 5

)

Upvotes: 4

Views: 730

Answers (1)

joran
joran

Reputation: 173737

Try this:

vec <- c(1,1,2,5,10)
> as.integer(factor(vec))
[1] 1 1 2 3 4

I realize now you mentioned the factor route. Personally I don't find it terribly offensive.

Or you could reach in the code of factor itself and do something mostly equivalent:

match(vec,unique(vec))

but that assumes that vec is sorted, so maybe you'd really have to do something like

match(vec,sort(unique(vec)))

Upvotes: 8

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