Reputation: 86657
Is it possible to override a class, but provide a specific implementation that must be provided if the overridden method is directly called on this method (and not on an super interface)?
class BaseService implements BaseInferface {
//something like this?
@Override //implements the interface
void run(<? extends BaseDTO) dto) {
}
}
class CustomService extends BaseService {
//CustomDTO extends BaseDTO
@Override
void run(CustomDTO dto) {
}
}
My goal is:
baseService.run(new BaseDTO()); //OK
customService.run(new BaseDTO()); //NOK as I want to make the CustomDTO required
Upvotes: 0
Views: 73
Reputation: 121702
You can do it like this:
interface BaseInterface<T extends BaseDTO>
{
void run(T dto);
}
class BaseService<T extends BaseDTO> implements BaseInterface<T>
{
}
class CustomService extends BaseService<CustomDTO>
{
}
Upvotes: 4