CODEWITHSUNDEEP
c#xmldeserialization
sexta13
sexta13

Reputation: 1568

Deserialize XML without a property

I have the following XML, but I'm not able to deserialize to the object I need.

<response>
          <texts>
                 <text name="blabla">This is bla</text>
                 <text name="test xpto">This is a text</text>
           (…)
           </texts>
</response>

This is what I've tried so far:

public class ResponseTexts : Response
{
    [XmlArray(ElementName = "texts")]
    [XmlArrayItem(ElementName = "text"]
    public List<Text> Texts { get; set; }
}

public class Text
{
    [XmlElement(ElementName = "text")]
    public string TextValue { get; set; }
    [XmlAttribute(AttributeName = "name")]
    public string Name { get; set; }
}

But so far the TextValue always come as null....can someone enlight me?

thanks in advance

Upvotes: 2

Views: 598

Answers (2)

Sergey Berezovskiy
Sergey Berezovskiy

Reputation: 236208

You should use XmlText to get element value. Here is correct serialziation attributes:

[XmlRoot("response")]
public class Response
{
    [XmlArray(ElementName = "texts")]
    [XmlArrayItem(ElementName = "text")]
    public List<Text> Texts { get; set; }
}

public class Text
{
    [XmlText]
    public string TextValue { get; set; }
    [XmlAttribute(AttributeName = "name")]
    public string Name { get; set; }
}

Deserialization:

var serializer = new XmlSerializer(typeof(Response));
using(var stream = File.OpenRead(path_to_xml))
{
   var response = (Response)serializer.Deserialize(stream);
}

Result:

{
  Texts: [
    { TextValue: "This is bla", Name: "blabla" },
    { TextValue: "This is a text", Name: "test xpto" }
  ]
}

Upvotes: 4

nuclear sweet
nuclear sweet

Reputation: 1121

In visual studio 2013: Copy your XML in buffer (just select it and press CTRL+C) go to Edit -> Paste Special -> Paste XML as Classes

Upvotes: 4

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