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David C. Rankin
David C. Rankin

Reputation: 84551

gnu c on_exit - segmentation fault

Out of curiosity I am trying to get the libc on_exit function to work, but I have run into a problem with a segmentation fault. The difficulty I am having is finding an explanation of the proper use of this function. The function is defined in glibc as:

Function: int on_exit (void (*function)(int status, void *arg), void *arg) This function is a somewhat more powerful variant of atexit. It accepts two arguments, a function and an arbitrary pointer arg. At normal program termination, the function is called with two arguments: the status value passed to exit, and the arg.

I created a small test, and I cannot find where the segmentation fault is generated:

#include <stdio.h>
#include <stdlib.h>

void *
exitfn (int stat, void *arg) {
  printf ("exitfn has been run with status %d and *arg %s\n", stat, (char *)arg);
  return NULL;
}

int
main (void)
{
  static char *somearg="exit_argument";
  int exit_status = 1;

  on_exit (exitfn (exit_status, somearg), somearg);
  exit (EXIT_SUCCESS);
}

Compiled with: gcc -Wall -o fn_on_exit fnc-on_exit.c

The result is:

$ ./fn_on_exit
exitfn has been run with status 1 and *arg exit_argument
Segmentation fault

Admittedly, this is probably readily apparent for seasoned coders, but I am not seeing it. What is the proper setup for use of the on_exit function and why in this case is a segmentation fault generated?

Upvotes: 0

Views: 744

Answers (1)

Ed Heal
Ed Heal

Reputation: 59997

The line of code

  on_exit (exitfn (exit_status, somearg), somearg);

Should be

  on_exit (exitfn, somearg);

As you do not want to call the exitfn at this stage (that returns NULL!)

Upvotes: 4

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