CODEWITHSUNDEEP
c++uppercaselowercasetoupper
Manisha Singh Sanoo
Manisha Singh Sanoo

Reputation: 929

Changing a lowercase character to uppercase in c++

Here is the code that i wrote. When i enter a lowercase character such as 'a', it gives me a blank character but afterwards it works well. Can you tell me what i did wrong? Thanks. :)

#include <iostream>
#include <string>
using namespace std;

int main()
{
    char letter;

    cout << "You will be asked to enter a character.";
    cout << "\nIf it is a lowercase character, it will be converted to uppercase.";
    cout << "\n\nEnter a character. Press . to stop: ";

    cin >> letter;

    if(islower(letter))
    {
        letter = isupper(letter);
        cout << letter;
    }

    while(letter != '.')
    {
        cout << "\n\nEnter a character. Press . to stop: ";
        cin >> letter;

        if(islower(letter))
        {
            letter = toupper(letter);
            cout << letter;
        }
    }

    return 0;
}

Upvotes: 10

Views: 96520

Answers (6)

YousefHany
YousefHany

Reputation: 11

#include <iostream>
using namespace std;

main()
{
    string name ;
    cout<<"Lower Case:  ";
    cin>>name;
    int  size_of_string = name.size(); // to detrmine the looping times
    cout<<"Upper case:  ";

    for(int i = 0 ,n = size_of_string ; i < n ; i++)
    {
        //check if the str[i] is lowercase 
        if(name[i]  >= 'a' && name[i]<='z' )
        {
            //convert the Lowercase to uppercase via ASCI Chart
            char a = name[i] - 32 ;
            cout<<a;
        }

        //the user input was upperCase 
        else
        cout<<name[i];
    }

    cout<<"\n Good Bye!"<<endl;
    return 0;
}

Upvotes: 0

JMBCODE
JMBCODE

Reputation: 15

In letter = isupper(letter);, you check whether the variable letter is capitalized, to convert it to uppercase you must use the function toupper()

letter = toupper(letter);

Upvotes: 0

hmofrad
hmofrad

Reputation: 1902

Generally speaking to convert a lowercase character to an uppercase, you only need to subtract 32 from the lowercase character as this number is the ASCII code difference between uppercase and lowercase characters, e.g., 'a'-'A'=97-67=32.

char c = 'b';
c -= 32; // c is now 'B'
printf("c=%c\n", c);

Another easy way would be to first map the lowercase character to an offset within the range of English alphabets 0-25 i.e. 'a' is index '0' and 'z' is index '25' inclusive and then remap it to an uppercase character.

char c = 'b';
c = c - 'a' + 'A'; // c is now 'B'
printf("c=%c\n", c);

Upvotes: 2

Rishi
Rishi

Reputation: 64

In case you want you own algorithm:

#include<iostream>
#include<string>

using namespace std;

int main()
{
    char ch = '/0';
    string input("Hello, How Are You ?");
    for(size_t i=0; i<input.length(); i++)
    {
        if(input[i]>=97 && input[i]<=122)
        {
            ch=input[i]-32;
        }
        else
        {
            ch = input[i];
        }
        cout << ch;
    }

  return 0;
}

Upvotes: 0

herohuyongtao
herohuyongtao

Reputation: 50667

Because you print a bool value (i.e. false, aka, NUL character here) in the first time.

You should change

letter = isupper(letter);

to

letter = toupper(letter);

Upvotes: 14

Marius Bancila
Marius Bancila

Reputation: 16318

Look here:

if(islower(letter))
{
    letter = isupper(letter);
    cout << letter;
}

If the character is lower, then you assigned it the return value of isupper. That should be 0. So you print a null character.

Why don't you just call toupper for every character that you enter? If it's lower it will convert it, if it is already upper it won't do anything.

Upvotes: 2

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