CODEWITHSUNDEEP
linuxsedawk
paultop6
paultop6

Reputation: 3761

How to remove the filename from the end of the du -h output?

Take the example:

$ du -h file_size.txt
112K file_size.txt

How would I remove the filename from the output of du -h?

I have tried to use sed to search for a string (the filename) and replace it with nothing, but it hasn't worked - command below:

du -h file_size.txt | sed 's/ 'file_size.txt'//'

Could someone please point out why this won't work, or perhaps a better way to do it?

Upvotes: 17

Views: 10857

Answers (9)

RARE Kpop Manifesto
RARE Kpop Manifesto

Reputation: 2915

why not just stat it ?

 stat -f '%z' vg1.mp4   # BSD-stat

821258414

gstat -c '%s' vg1.mp4   # GNU-stat

821258414

if u insist on the du way, getting first column is cleaner than mentioned :

du -smh vg1.mp4 | awk NF=1 

783M

or the wc way - using < redirection sends the file over the pipe, so u don't need to trim out the filename —- somehow BSD-wc pads in an extra space

gwc -c < vg1.mp4    # GNU-wc      

821258414

 wc -c < vg1.mp4    # BSD-wc

 821258414

Upvotes: 1

Aeronautix
Aeronautix

Reputation: 316

To deal with filenames containing newlines:

$ du -h $'./filename\nwith\nnewlines.txt' | awk 'NR==1 { print $1 }'
4.0K

There's a really cool sed solution, using a "print and quit" trick, pulled from here:

$ du -h $'./filename\nwith\nnewlines.txt' | sed -E -n '/(.*)\t.*/{s//\1/p;q;}'
4.0K

Most of the other answers on here can't deal with newlines (except for ghostdog's set answer):

$ du -h $'./filename\nwith\nnewlines.txt' | cut -f1
4.0K
with
newlines.txt

Upvotes: 0

ghostdog74
ghostdog74

Reputation: 342969

the output of du -h is [tab] delimited. 

du -h file_size.txt |sed 's/[\t].*//g'

Upvotes: 0

Peter Westlake
Peter Westlake

Reputation: 5036

Your original command would have worked except that you are including a space in the sed regexp, and du outputs tabs.

Upvotes: 0

ghostdog74
ghostdog74

Reputation: 342969

@OP if your data has distinct fields, for example spaces/tabs, then its easier to use tools like awk/cut to split them on those fields by delimiters. Using regex (eg sed ) is not necessary. Even better is just using the shell.

various ways

$ du -h file | awk '{print $1}'
4.0K

$ du -h file | cut -f1
4.0K

$ set -- $(du -h file) #using shell only
$ echo $1
4.0K

Upvotes: 0

vezult
vezult

Reputation: 5243

This is a little more verbose, but in any case, this is another way to what you want:

du -h file_size.txt |while read x junk; do echo $x; done

Upvotes: 0

tux21b
tux21b

Reputation: 94799

Simple output the first column. Here is the awk solution

du -h test.txt  | awk '{ print $1 }'

Upvotes: 5

Carl Norum
Carl Norum

Reputation: 225162

You have some bad quoting in that command line. The simplest is probably:

du -h file_size.txt | cut -f -1

To fix your command line:

du -h file_size.txt | sed 's/file_size.txt//'

Since your post has an awk tag:

du -h file_size.txt | awk '{ print $1 }'

Upvotes: 22

Tomalak
Tomalak

Reputation: 338376

du -h file_size.txt | cut -f1

Upvotes: 14

Related Questions