CODEWITHSUNDEEP
linuxsedawktcsh
Drago
Drago

Reputation: 101

How to delete all lines between the pattern lines

I have text with either the following structure

bla bla more bla bla
$ 
PART  /  4402000LLINK    4401001
NAME ADHESIVE   8.0 mm LLINK Property                                           


        8.                  8.         2
END_PART
$
some other bla bla

But the line containing PART could be also:

PART  /  4402000   LLINK 4401001

or:

PART  /  4402000  LLINK  4401001

So strictly speaking the LLINK could occupy the columns from 16 to 23. Now I would like to delete all lines between the pattern lines. First pattern is line containing both PART and this LLINK. The second pattern is line containing END_PART. So at the end I will have this:

bla bla more bla bla 
$
$
some other bla bla

I am using CentOS with:

> echo $SHELL
/bin/tcsh

so, I can use sed or awk in tcsh e.g. Could you help. Thank you

Upvotes: 0

Views: 96

Answers (2)

jrjc
jrjc

Reputation: 21903

With awk, this seems to work :

$ cat file

bla  PART bla more bla bla
$ 
PART  /  4402000LLINK    4401001
NAME ADHESIVE   8.0 mm LLINK Property                                           
PART

        8.                  8.         2
END_PART
$
some other bla bla
AAAAA
PART  /  4402120   LLINK    4401001
NAME ADHESIVE   8.0 mm LLINK Property
PART
AAAAAAAAAA
        8.                  8.         2
END_PART
$AAAA
AAAAAsome other bla bla

awk '{if (($0!~/PART/ || $0!~/LLINK/) && stop == 0) {print} else {if ($0~/END_PART/) {stop=0} else {stop=1}}}' file

bla  PART bla more bla bla
$ 
$
some other bla bla
AAAAA
$AAAA
AAAAAsome other bla bla

Hope this helps !

Upvotes: 0

clement
clement

Reputation: 3375

This sed command can be used.

sed -i -r '/PART.*LLINK/,/END_PART/d' file

Upvotes: 3

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