CODEWITHSUNDEEP
qtdebuggingqt-creatorqstring
Martin Delille
Martin Delille

Reputation: 11780

Qt Creator debugger step into QString code

When debugging with Qt Creator, each time I step into a method with a QString as parameter I reach some annoying qstring.h code:

// ASCII compatibility
#ifndef QT_NO_CAST_FROM_ASCII
inline QT_ASCII_CAST_WARN QString(const char *ch)
    : d(fromAscii_helper(ch, ch ? int(strlen(ch)) : -1))
{}

Is there a way to avoid the debugger to step into qstring.h?

Edit 1

My pro file:

QT       += core
QT       -= gui
TARGET = ConsoleTest03
CONFIG   += console
CONFIG   -= app_bundle
TEMPLATE = app
SOURCES += main.cpp

My code:

#include <QDebug>
#include <QString>

void display(QString s)
{
    qDebug() << s;
}

int main(int argc, char *argv[])
{
    display("coucou");
    return 0;
}

Edit 2

I use Qt 5.1.1 and Qt 3.0.1.

Upvotes: 4

Views: 801

Answers (1)

user3427419
user3427419

Reputation: 1779

You get there because you are calling that constructor in your code.

display("coucou");

that actually calls

display(QString("coucou"));

and QString(const char*) is not something you really should be doing away. http://qt-project.org/doc/qt-5/qstring.html#QString-8.

You can disable stepping into the constructor by not calling it on that line

QString str(QLatin1String("coucou")); // you don't really need QLatin1String
                                      // if you are happy with 'const char*' constructor
display(str);

And now, you no longer get QString constructor on the display() line. Alternatively, make a breakpoint on display() function and instead of Step In, do a Continue.

You are also calling QString copy constructor because your function takes a QString, not a reference or pointer to the actual object. This should be very easy to spot this in a debugger instead of calling it "annoying". So, here's some code that is guaranteed to let you step into display() without anything else,

#include <QDebug>
#include <QString>

void display(const QString &s)
{
    qDebug() << s;
}

int main(int argc, char *argv[])
{
    QString str(QLatin1String("foo"));
    display(str);
    return 0;
}

I hope this is now very, very clear.

Upvotes: 1

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