CODEWITHSUNDEEP
xmlxsltxslt-1.0
user3427584
user3427584

Reputation: 13

Muenchian grouping and /*

Using Muenchian grouping in XSLT 1.0. When used in apply-templates it works for the first <level> element then fails to output for further <level> elements.

Sample input XML: note that the siblings of <areas> can be variable

 <levels>
   <level>
     <areas>      
       <p1>A</p1>
       <p1>B</p1>
       <p2>C</p2>
     </areas>      
   </level>
   <level>
     <areas>
       <p3>C</p4>
       <p3>D</p3>
       <p4>E</p4>      
     </areas>
   </level>
 </levels>

Sample XSLT:

<xsl:key name="names" match="*/areas/*" use="local-name(.)" />

<xsl:template match="/levels/*">
  <xsl:apply-templates select="./areas/*[generate-id(.)=generate-id(key('names', local-name(.)))]" mode="A" />
</xsl:template>

<xsl:template match="*" mode="A">
  <xsl:variable name="category" select="local-name(.)" />
  <xsl:element name="{$category}">
  </xsl:element>
</xsl:template>

Desired output:

<p1>
<p2>
<p3>
<p4>

Output returned:

<p1>
<p2>

Any ideas on why it ignores the second <level> element?

Thanks.

Upvotes: 1

Views: 84

Answers (1)

Martin Honnen
Martin Honnen

Reputation: 167516

You could change

<xsl:template match="/levels/*">
  <xsl:apply-templates select="./areas/*[generate-id(.)=generate-id(key('names', local-name(.)))]" mode="A" />
</xsl:template>

to

<xsl:template match="/levels">
  <xsl:apply-templates select="level/areas/*[generate-id(.)=generate-id(key('names', local-name(.)))]" mode="A" />
</xsl:template>

Upvotes: 1

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