CODEWITHSUNDEEP
phparraysregexmultidimensional-arraypreg-replace
Carey
Carey

Reputation: 670

Implement preg_replace() on a 2d array

I have a relatively large array of elements which I want to search for a string and replace any matches. I'm currently trying to do this using preg_replace and regular expressions:

preg_replace("/\d?\dIPT\.\w/", "IPT", $array);

I want to get all values which match either 00IPT.A or 0IPT.A (with 0 representing any numerical character and A representing any letter) and replace them with IPT. However, I'm getting array to string conversion notices. Is there any way to get preg_replace to accept an array data source? If not, is there any other way I could achieve this?

The documentation says that preg_replace should be able to accept array sources — this is the reason I'm asking.

The string or an array with strings to search and replace. If subject is an array, then the search and replace is performed on every entry of subject, and the return value is an array as well.

The array is multidimensional if that helps (has multiple arrays under one main array).

Upvotes: 8

Views: 33609

Answers (3)

Tom Fenech
Tom Fenech

Reputation: 74695

preg_replace doesn't modify in place. To permanently modify $array, you simply need to assign the result of preg_replace to it:

$array = preg_replace("/\d{1,2}IPT\.\w/", "IPT", $array);

works for me.

$array = array('00IPT.A', '0IPT.A');
$array = preg_replace("/\d{1,2}IPT\.\w/", "IPT", $array);
var_dump($array);
// output: array(2) { [0]=> string(3) "IPT" [1]=> string(3) "IPT" }

Note: the \d{1,2} means one or two digits.

If you want to do this to a two-dimensional array, you need to loop through the first dimension:

$array = array( array('00IPT.A', 'notmatch'), array('neither', '0IPT.A') );    
foreach ($array as &$row) {
    $row = preg_replace("/\d{1,2}IPT\.\w/", "IPT", $row);
}
var_dump($array);

output:

array(2) { 
    [0]=> array(2) { 
        [0]=> string(3) "IPT" 
        [1]=> string(8) "notmatch" 
    } 
    [1]=> &array(2) { 
        [0]=> string(7) "neither" 
        [1]=> string(3) "IPT" 
    } 
}

Note that you have to loop through each row by reference (&$row) otherwise the original array will not be modified.

Upvotes: 16

just somebody
just somebody

Reputation: 19257

your $array contains some further arrays. preg_replace works fine with arrays of strings, but not with arrays of arrays [of arrays...] of strings.

Upvotes: 1

Andresch Serj
Andresch Serj

Reputation: 37438

Your value does not sit in the array as a simple element but as a subset right? Like so?

array (
  array ('id' => 45, 'name' => 'peter', 'whatyouarelookingfor' => '5F'),
  array ('id' => 87, 'name' => 'susan', 'whatyouarelookingfor' => '8C'),
  array ('id' => 92, 'name' => 'frank', 'whatyouarelookingfor' => '9R')
)

if so:

<?php

foreach ($array as $key => $value) {
  $array[$key]['whatyouarelookingfor'] =  
    preg_replace("/\d?\dIPT\.\w/", "IPT", $value['whatyouarelookingfor']);
}

Or if more elements have this, just go broader:

<?php

foreach ($array as $key => $value) {
  $array[$key] =  
    preg_replace("/\d?\dIPT\.\w/", "IPT", $value);
}

Upvotes: 1

Related Questions