CODEWITHSUNDEEP
javaregex
lowcoupling
lowcoupling

Reputation: 2169

Java Regex in round brackets

I am trying to parse an input string like this

String input = "((1,2,3),(3,4,5),(2,3,4),...)"

with the aim of getting an array of String where each element is an inner set of integers i.e. 

array[0] = (1,2,3)
array[1] = (3,4,5)

etc.

To this end I am first of all getting the inner sequence with this regex:

String inner = input.replaceAll("\\((.*)\\)","$1");

and it works. Now I'd like to get the sets and I am trying this

String sets = inner.replaceAll("((\\((.*)\\),?)+","$1")

But I can't get the result I expected. What am I doing wrong?

Upvotes: 1

Views: 2188

Answers (1)

Rohit Jain
Rohit Jain

Reputation: 213391

Don't use replaceAll to remove the parentheses at the ends. Rather use String#substring(). And then to get the individual elements, again rather than using replaceAll, you should use String#split().

String input = "((1,2,3),(3,4,5),(2,3,4))";
input = input.substring(1, input.length() - 1);

// split on commas followed by "(" and preceded by ")"
String[] array = input.split("(?<=\\)),(?=\\()");

System.out.println(Arrays.toString(array));

Upvotes: 3

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