CODEWITHSUNDEEP
c#asp.net-mvcpartial-views
Craig
Craig

Reputation: 18734

Passing a model with a Partial View

I want to show a view on some of my forms, which shows a list of alerts, read from a database table. I think I need to use a partial view - but haven't used one.

So far, I created a partial view in my shared views folder called "_Alerts.cshtml".

In that file, at the moment, I simply have:

@{
    Layout = null;
}

This is a shared view.

This is just me trying to display something.

And then, on my existing page, on which I want to display the alerts, I have this section of code:

@if (User.Identity.IsAuthenticated)
{
    <div class="row">
        @Html.Partial("~/Views/Shared/_Alerts.cshtml", null)
    </div>
}

This works. However, my understanding is not right. At the moment, I pass no model to it. Is there no controller for the partial view? At the moment, I need to create a controller method - somewhere - that gets me a list of alerts from my data service, and then I want to format that and present it in the partial view. But I am unsure where the controller methods go. If this view is called from 8 different screens, would the 8 controllers for these screens have a call to get my alerts, and format them?

Seems like a lot of duplication.

Upvotes: 1

Views: 168

Answers (2)

Andy T
Andy T

Reputation: 9901

If you have all the data you need to pass into the partial, then you can use the @Html.Partial and pass in the model.

If on the other hand, you want the view you are embedding to get the data itself, then you would use Html.RenderAction

Upvotes: 1

scartag
scartag

Reputation: 17680

They need not be duplication.

You can define the action you want inside a controller and call @Html.Action instead of @Html.Partial

Inside you action you can return a partial view.

public class AlertsController : Controller 
{
   public ActionResult Show()
   {
     var model = GetModel();//decide where this will come from.

     return PartialView("~/Views/Shared/_Alerts.cshtml",model);
   }

}

In your layout view or wherever you need to use it. you can simply call it as below.

@Html.Action("Show","Alerts")

Upvotes: 1

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