CODEWITHSUNDEEP
java
mstfdz
mstfdz

Reputation: 2796

how to use primitive types properly

int x = 10;
int y = 10;

Integer x1 = new Integer(10);
Integer y1 = new Integer(10);

System.out.println(x == y);
System.out.println(x1 == y1);

The first sop will print true whereas the second one will print false. What is the actual problem ?

Upvotes: 0

Views: 91

Answers (3)

Shekhar Khairnar
Shekhar Khairnar

Reputation: 2691

first sop print true because int x and y contains same bit pattern for 10.

In second approach x1 and y1 are both different object reference variable of Integer type so they are point to different object in memory that's why in second sop you will get false.

if you want to check two Integer's equality you can use 

x1.equals(y1)

it will return true.

Upvotes: 0

RKC
RKC

Reputation: 1874

The second one is comparing Object Id's.Since every object is having a unique Id it is returning false.

Upvotes: 2

user432
user432

Reputation: 3534

The second approach is not checking the values rather the objects.

If you want to compare the values of 2 Integer objects you would have to use appropriate methods like compareTo(Integer)

Like mentioned in the comments if you want to check for equality only you can use equals

Upvotes: 2

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