Reputation: 1609
I have month and value columns in a table,like
Month Value Market
2010/01 100 1
2010/02 200 1
2010/03 300 1
2010/04 400 1
2010/05 500 1
2010/01 100 2
2010/02 200 2
2010/03 300 2
2010/04 400 2
2010/05 500 2
What I want to do is get new Month and Value combinations using (value in month(n-1)+value in month(n))/2=value in month n, also this calculation is based on market column, it group by market number. So, for the above example, the new month and value combination should be
Month Value Market
2010/01 null 1
2010/02 (100+200)/2 1
2010/03 (200+300)/2 1
2010/04 (300+400)/2 1
2010/05 (400+500)/2 1
2010/01 null 2
2010/02 (100+200)/2 2
2010/03 (200+300)/2 2
2010/04 (300+400)/2 2
2010/05 (400+500)/2 2
Do you know how to achieve it in Oracle? Thank you!
Upvotes: 1
Views: 89
Reputation: 67722
If there is no gap in your data, you can use LAG
:
SQL> WITH DATA AS (
2 SELECT DATE '2010-01-01' mon, 100 val FROM dual UNION ALL
3 SELECT DATE '2010-02-01' mon, 200 val FROM dual UNION ALL
4 SELECT DATE '2010-03-01' mon, 300 val FROM dual UNION ALL
5 SELECT DATE '2010-04-01' mon, 400 val FROM dual UNION ALL
6 SELECT DATE '2010-05-01' mon, 500 val FROM dual
7 )
8 SELECT mon, (LAG(val) OVER (ORDER BY mon) + val) / 2 avg_val FROM DATA;
MON AVG_VAL
----------- ----------
01/01/2010
01/02/2010 150
01/03/2010 250
01/04/2010 350
01/05/2010 450
However, if there is a gap the result might not be what you expect. In that case, you can either use a self-join or narrow the windowing clause:
SQL> WITH DATA AS (
2 SELECT DATE '2010-01-01' mon, 100 val FROM dual UNION ALL
3 SELECT DATE '2010-02-01' mon, 200 val FROM dual UNION ALL
4 SELECT DATE '2010-03-01' mon, 300 val FROM dual UNION ALL
5 /* gap ! */
6 SELECT DATE '2010-05-01' mon, 400 val FROM dual UNION ALL
7 SELECT DATE '2010-06-01' mon, 500 val FROM dual
8 )
9 SELECT mon, (first_value(val)
10 OVER (ORDER BY mon
11 RANGE BETWEEN INTERVAL '1' MONTH PRECEDING
12 AND INTERVAL '1' MONTH PRECEDING)
13 + val) / 2 avg_val
14 FROM DATA;
MON AVG_VAL
----------- ----------
01/01/2010
01/02/2010 150
01/03/2010 250
01/05/2010
01/06/2010 450
Upvotes: 5
Reputation: 132570
This does it:
SQL> select month,
2 (value+lag(value) over (order by month))/2 as value
3* from t1
MONTH VALUE
---------- ----------
2010/01
2010/02 150
2010/03 250
2010/04 350
2010/05 450
5 rows selected.
Upvotes: 3