CODEWITHSUNDEEP
rubyruby-1.8.7
user2071444
user2071444

Reputation:

Compare multidimensional array and return index

Ruby 1.8.7

array = [[1.5,"cm"],[1.5,"cm"],[1.5,"m"]]

How to compare each array inside the variable array and see if it is equal, if equal then move on else if not equal then return the index of the array element which was not equal and stop comparing.

So in this example, 

array[0] == array[1] 
#=> true

Thus, move on 

array[1] == array[2]
=> false

Hence return index i.e = 1

return 1

Upvotes: 0

Views: 659

Answers (2)

Arup Rakshit
Arup Rakshit

Reputation: 118271

Here is how I would do using Array#each_index :

def compare_array_elements(array)
  siz = array.size - 1
  array.each_index { |i| return i if i != siz && array[i] != array[i+1] }
  nil
end

array = [[1.5,"cm"],[1.5,"cm"],[1.5,"mm"]] 
compare_array_elements(array) # => 1

array = [[1.5,"cm"],[1.5,"cm"],[1.5,"cm"]]
compare_array_elements(array) # => nil

Upvotes: 4

sawa
sawa

Reputation: 168101

[[1.5,"cm"],[1.5,"cm"],[1.5,"m"]]
.each_cons(2).with_index(1).find{|(a, b), i| a == b}.last
# => 1

Upvotes: 0

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