CODEWITHSUNDEEP
node.jsexpresswebrtceasyrtc
user3437333
user3437333

Reputation: 11

how to resolve following easyrtc issue?

I've written following code:

var http    = require("http");              // http server core module
var express = require("express");           // web framework external module
var io      = require("socket.io");         // web socket external module
var easyrtc = require("easyrtc");           // EasyRTC external module
var app = express();

var server = http.createServer(app).listen(app.get('port'));

io= io.listen(server,{"log level":1});
var rtc = easyrtc.listen(server, io);

this is giving following error:

$node server info - EasyRTC: Starting EasyRTC Server (v1.0.10) on Node (v0.10.26) [TypeError: Object # has no method 'get'] TypeError: Object # has no method 'get' at async.waterfall.pub.socketServer.sockets.on.easyrtcid (/home/ritzy1/Downloads/downloaded codes/VEDIO/change2/testexpandwb/node_modules/easyrtc/lib/easyrtc_default_event_listeners.js:1472:29) at fn (/home/ritzy1/Downloads/downloaded codes/VEDIO/change2/testexpandwb/node_modules/easyrtc/node_modules/async/lib/async.js:582:34) at Object._onImmediate (/home/ritzy1/Downloads/downloaded codes/VEDIO/change2/testexpandwb/node_modules/easyrtc/node_modules/async/lib/async.js:498:34) at processImmediate [as _immediateCallback] (timers.js:330:15)

Ηow can i fix it?

Upvotes: 1

Views: 999

Answers (1)

BeingMIAkashs
BeingMIAkashs

Reputation: 1385

You have to give a specific port number in the listen() function. Change the following line
var server = http.createServer(app).listen(app.get('port'));
with
var server = http.createServer(app).listen(8080);
Note : 8080 is a port number you can specify any other port number which are not currently using.

Happy coding

Upvotes: 1

Related Questions