Reputation: 137
I've got a problem making a system to enable users to favorite posts. I know I'm missing something in here, but I'm not sure what and I don't know how to fix it so that it works.
mysql_select_db($database_connection, $connection);
$query_deltakelse = "SELECT brukernavn, postID FROM deltakelse";
$deltakelse = mysql_query($query_deltakelse, $connection) or die(mysql_error());
$row_deltakelse = mysql_fetch_assoc($deltakelse);
$totalRows_deltakelse = mysql_num_rows($deltakelse);
$username=$_SESSION['valid_user'];
if(in_array($_POST['id'], $row_deltakelse))
{
mysqli_query($connection,"DELETE FROM deltakelse WHERE postID='id'");
}
else
{
mysqli_query($connection,"INSERT INTO bruker (brukernavn, postID) VALUES ('$username', '$id')");
}
$(document).ready(function() {
$('.delta').on('click', null, function() {
var _this = $(this);
var post_id = _this.data('id');
$.ajax({
type : 'POST',
url : '/file.php',
dataType : 'json',
data : 'id='+ post_id,
complete : function(data) {
if(_this.text() == 'Fave this')
{
_this.html('Faved!');
}
else
{
_this.html('Fave this');
}
}
});
});
});
<a href="#" class="delta" data-id="<?php echo $post_id; ?>">Favorite</a>
Upvotes: 0
Views: 88
Reputation: 219864
You're mixing mysql and mysqli functions. You can't do that.
This is MYSQL
mysql_select_db($database_connection, $connection);
$query_deltakelse = "SELECT brukernavn, postID FROM deltakelse";
$deltakelse = mysql_query($query_deltakelse, $connection) or die(mysql_error());
$row_deltakelse = mysql_fetch_assoc($deltakelse);
$totalRows_deltakelse = mysql_num_rows($deltakelse);
$username=$_SESSION['valid_user'];
Here you use MySQLi with a MySQL resource. That won't work.
if(in_array($_POST['id'], $row_deltakelse))
{
mysqli_query($connection,"DELETE FROM deltakelse WHERE postID='id'");
}
else
{
mysqli_query($connection,"INSERT INTO bruker (brukernavn, postID) VALUES ('$username', '$id')");
}
Change that, too:
if(in_array($_POST['id'], $row_deltakelse))
{
mysql_query("DELETE FROM deltakelse WHERE postID='id'", $connection);
}
else
{
mysql_query("INSERT INTO bruker (brukernavn, postID) VALUES ('$username', '$id')", $connection);
}
Upvotes: 1