CODEWITHSUNDEEP
javascriptjqueryasp.net-mvcjson
Cybercop
Cybercop

Reputation: 8678

MVC: While retrieving the passed Json object from controller in view, JavaScript error

I'm passing some string messages as Json object in view.

public ActionResult SomeAction(someObject object)
{            
    .....
    .....
    
    if (check1)
    {
        return Json(new { error = Resource.someMessage1},JsonRequestBehavior.AllowGet);
    }
    if(check2)
    {
        return Json(new { error = Resource.someMessage2}, JsonRequestBehavior.AllowGet);
    }
 
    //some stuffs

    return Json(new {success = "success"}, JsonRequestBehavior.AllowGet);
}

I want to retrieve the messages passed from controller and alert from My view

in view I have some javascript

function done(data) {
    alert("hello");
    var message = JSON.parse(data);
    alert(message);
    if (message["error"] != undefined) {
        alert(message["error"]);
    } else {
     //do some stuff

    }
};

what I was expecting is if passed message from controller is type error then I would get alert with the message.

The line alert("hello"); but there is no alert after that. I get error in console

enter image description here

Am I doing something wrong?

Upvotes: 1

Views: 525

Answers (4)

Faiz Mohamed Haneef
Faiz Mohamed Haneef

Reputation: 3596

the variable type is detected as json object. 

var x = {"error":"somemessage"};
alert(x.error)

The variable is detected as String here.

var x = JSON.parse('{"error":"somemessage"}'); alert(x.error)

If you notice, the difference is #1 starts with {(curly braces) whereas #2 starts with '(apostrophe)

Upvotes: 1

Sai Avinash
Sai Avinash

Reputation: 4753

You have to use data.sucess to get your result . There is no need to parse again.

Upvotes: 0

pawels
pawels

Reputation: 1120

Try not parsing the answer (so remove "JSON.parse(data)" line) and read everything directly from "data" variable.

Upvotes: 0

Yasser Shaikh
Yasser Shaikh

Reputation: 47774

If you execute the following line of code 

var a = { success : "success" };
var b = JSON.parse(a);

you will get the error you have mentioned about "SyntaxError: Unexpected token o..."

Don't know why are you trying to convert your already JSON object using JSON.parse(), instead you could use this

a.success

to read the "success" value .

Upvotes: 2

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