Reputation: 335
I have class A how to overload operator == to perform
A a,b,c;
if (a==b==c) {}
Could anyone help me?
Upvotes: 1
Views: 263
Reputation: 106076
It can be done, and it's very occasionally useful as a kind of domain-specific language (DSL) for matching the notation expected by non-C++-programmers, but it should be studiously avoided for other uses as it'll confound (and annoy) programmers working on the code if this is used willy-nilly.
class A
{
// ...
bool equals(const A& rhs) const { return ... }
struct X
{
X(const A& a, bool b) : a_(a), b_(b) { }
X& operator==(const A& rhs) const { b_ &= a_.equals(rhs); return *this; }
explicit operator bool() const { return b_; }
// remove explicit pre C++11 / consider making it operator void*() ...
const A& a_;
mutable bool b_;
};
X A::operator==(const A& rhs) const
{
return X(*this, equals(rhs));
}
};
(You might prefer standalone functions if you have implicit constructors).
The same kind of proxy-using hackery allows all manner of unexpected notations like 3 < x < 9
and x == a1 || a2 || a3
... again, avoid them unless it'll make a huge difference to the maintainers of the code where they'll be used (and ideally that code will have very clear boundaries from the other C++ code in your system).
As an example of good uses of such techniques, consider the boost spirit library and it's unusual use of a lot of operators to provide something approximating BNF notation....
Upvotes: 2
Reputation: 24576
Very short answer: NO!
Slightly longer answer: Don't try this.
Explanation: Every C++ programmer is used to have the comparison operator return a bool or something convertible to bool. Just because it's natural to type things like if (a==b)
.
So if the expression a==b
returns a bool x
, then a==b==c
would mean comparing x
with c
. Which makes no sense at all. Even if you get it to compile, e.g. comparing ints that way, it would not yield the result you expect.
So, while there technically I can think of a solution to what you seem to want (compare if all three are equal), the right thing to do is how it is always done in C++: logically chain binary comparisons:
if (a==b && b==c) {}
for the ones who wonder about the "technical doable but oh so ugly" solution:
(DON'T DO THIS IN REAL WORLD USE! You should get fired if you do.)
template <class T>
struct multiCompareProxy {
bool b;
T const& t;
explicit operator bool() const {return b;}
multiCompareProxy operator==(T const& rhs) {
return {b && t.equals(rhs), t};
}
};
template <class T>
multiCompareProxy<T> operator==(T const& lhs, T const& rhs) {
return {lhs.equals(rhs), lhs};
}
A class now just has to overload the euqals
method for this to work: Example
Upvotes: 3
Reputation: 2943
You cannot (minus the possibility of an ugly hack) overload operator==(...)
to work as you have specified.
If you think about what it would do a == b
would become either true or false (a bool), then you would have (<bool> == c)
left. The proper way to do what you are looking to do would be some form of (a==b) && (b==c)
.
There are times when you can overload an operator to work as you describe, but it would have to return the same type that it takes. An example would be:
class A
{
A& operator+=(A const& rhs)
{
// operator logic
return *this;
}
}
This case works because with a += b += c
, you would perform (b += c)
which would return an A&
, which the remaining a.operator+=(...)
accepts as an argument.
Upvotes: 1
Reputation: 21317
If for whatever reason you really wanted to do this, you'd need a proxy object like so:
struct A {};
struct Proxy {};
Proxy operator==(const A& a, const A& b) {
return {};
}
bool operator==(const Proxy& p, const A& b) {
return true;
}
bool operator==(const A& a, const Proxy& p) {
return true;
}
#include <iostream>
int main() {
A a, b, c;
if(a == b == c) {
std::cout << "Bad.\n";
}
}
But don't do this. Use (a == b) && (a == c)
like everyone else.
Upvotes: 2
Reputation: 608
I would write:
bool operator==(const A& lhs, const A& rhs){ /* do actual comparison */ }
And use it twice with and operation.
Upvotes: 0
Reputation: 7663
bool operator==(T const & a, T const & b) {
return /*boolean expr*/
}
if you have a class you can do:
class MyClass {
public:
bool operator==(T const & rhs) const {
return /*boolean expr*/
}
}
And don't use == twice in a row, you can't, do:
a == b && b == c
Upvotes: 0