CODEWITHSUNDEEP
phparraysvariables
user1551496
user1551496

Reputation: 169

Countries Array check for value

I'm looking for a solution to check an array if country-code exists. And than post the whole name.

I'm new in PHP so I'm not shure if in_array is the right way :)

The php code

$country = "al"

<?php if (in_array("$country", $countries_en)) {
        echo "$country"; }
    ?>

So the echo what i want is not "al". I want "Albania".

The array:

$countries_en = array
(
    'ad' => 'Andorra',
    'ae' => 'United Arab Emirates',
    'af' => 'Afghanistan',
    'ag' => 'Antigua and Barbuda',
    'ai' => 'Anguilla',
    'al' => 'Albania',
    'am' => 'Armenia,..... and much more

Upvotes: 0

Views: 713

Answers (4)

nanobash
nanobash

Reputation: 5500

Try array_walk function:

$country = 'ai';

$countries_en = array(
    'ad' => 'Andorra',
    'ae' => 'United Arab Emirates',
    'af' => 'Afghanistan',
    'ag' => 'Antigua and Barbuda',
    'ai' => 'Anguilla'
);

array_walk($countries_en, function($value,$key) use ($country) {
    if ($country === $key) {
        echo $value; // result "Anguilla"
    }
});

Upvotes: 1

user2469730
user2469730

Reputation: 35

As a solution to your problem please try executing following code snippet
  <?php 
   $country='al';
   if(isset($countries_en[$country]))
   { 
         echo $countries_en[$country];
   }
?>

Upvotes: 1

John Conde
John Conde

Reputation: 219884

Just use $country as the key to get the value you want from the $country_en array:

$country = "al";

if (array_key_exists($country, $countries_en)) {
    echo $country_en[$country]; 
}

You want to use array_key_exists() here, not in_array() as al is one of the array keys, not a value.

Upvotes: 3

Anand Solanki
Anand Solanki

Reputation: 3425

Try this:

Here "al" is used as key of array, not value and in_array() function checks for value.

So, you need to use another function array_key_exists() here.

<?php if (array_key_exists($country, $countries_en)) {
    echo $country_en[$country]; }
?>

Upvotes: 2

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