Reputation: 25
I'm trying to parse JSON data which is coming from this url.
But I am getting these errors:
03-27 16:48:21.019: E/Buffer Error(23717): Error converting result java.lang.NullPointerException
03-27 16:48:21.059: E/JSON Parser(23717): Error parsing data org.json.JSONException: End of input at character 0 of
Wwhen I debug my code; getJsonFromUrl()
method returns null jobject. Here is the JSONParser class which I used. What's causing the error?
public class JSONParser {
static InputStream iStream = null;
static JSONArray jarray = null;
static JSONObject jObj= null;
static String json = "";
public JSONParser() {
}
public JSONObject getJSONFromUrl(String url) {
// Making HTTP request
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
try {
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
InputStream is = httpEntity.getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
iStream.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parsing the string to a JSON object
try {
if (json != null) {
jObj = new JSONObject(json);
} else {
jObj = null;
}
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
I'm making the call for this method from another class using these lines. (url parameter is defined at top)
JSONParser jParser = new JSONParser();
final JSONObject jobject = jParser.getJSONFromUrl(url);
Upvotes: 1
Views: 12649
Reputation: 10514
You are trying to get the JSON content using a HTTP POST method instead of the appropiated GET method (W3schools.com GET vs.POST), modify your source code to simplify and fix your HTTP request
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet get = new HttpGet(url);
try {
HttpResponse httpResponse = httpClient.execute(get);
String json = EntityUtils.toString(httpResponse.getEntity());
System.out.println(json);
....
....
} catch (Exception e) {
....
}
Upvotes: 1