CODEWITHSUNDEEP
python
user3072782
user3072782

Reputation: 49

Output file formatting

I want my output file format to be like this :

file_out.write("{0},{2},{3},{4},{5},{6},{7},{8},{9},{9},{10},{11},{12},{13},{14},{15},{16},{17},{18},{19},{20},{21},{22},{23},{24},{25},{26},{27},{28},{29}\n".format(*frequency_count(seq)))

Basically I want to write a file that contains item one until 30 . I tried to do something like this

file_out.write("{0}:{29}\n".format(*frequency_count(seq)))

but i only get the 1st item and the last item. How do I write such that my output file contains all items without having to write all of them in my command.

The items are integers from a list of something.

Upvotes: 1

Views: 66

Answers (3)

Remolten
Remolten

Reputation: 2682

Try this:

for i in range(30):
    write_me += '{%d},' % i

write_me += '\n'
file_out.write(write_me).format(*frequency_count(seq))

It should work just ask questions below.

EDIT: Just realized I misunderstood the question disregard thsi

Upvotes: 0

mtadd
mtadd

Reputation: 2555

Assuming you want the first 30 items returned from frequency_count comma-delimited, try the following:

file_out.write(','.join(map(str,frequency_count(seq)[:30])) + '\n')

Upvotes: 3

alecxe
alecxe

Reputation: 473873

You can simply join items by ,:

file_out.write(','.join(frequency_count(seq)))

You may also need to cast list items to string before joining:

file_out.write(','.join(map(str, frequency_count(seq))))

Upvotes: 1

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