CODEWITHSUNDEEP
unixfindaix
Martin Nielsen
Martin Nielsen

Reputation: 2049

UNIX(AIX): How can i list all files in a directory that is NOT in a list

I am looking for a way to list the contents of a directory on a UNIX system, that does not appear in a predefined "exclude" list.

Say i have a dir:

dir1
    dir1-1
        test1
        test2
        test3
    dir1-2
        test4
        test5

and an "exclude list" as such:

dir1/dir1-1/test1
dir1/dir1-2/test5

I am interested in outputting

dir1/dir1-1/test2
dir1/dir1-1/test3
dir1/dir1-2/test4

And the actual command will be with both an exclude list and a directory structure with thousands of files, so performance is a bit of an issue.

Any ideas?

Upvotes: 1

Views: 442

Answers (1)

fedorqui
fedorqui

Reputation: 290025

You can exclude them with the ! operator:

find . -type f ! \( -path "./dir1-1/test1" -o -path "./dir1-2/test5" \)

Note we are hardcoding the excludee path from the .. So in case you execute it from another place you will need to add the corresponding path. Or, better, use full paths like:

find /your/path/ -type f ! \( -path "/your/path/dir1-1/test1" -o -path "/your/path/dir1-2/test5" \)

Upvotes: 2

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