CODEWITHSUNDEEP
javajava-8java-stream
djhworld
djhworld

Reputation: 6776

Java 8 streams - each step in the chain evaluated for entire input or do items get passed through?

Say if I have this trivial program

    List<String> input = Arrays.asList("1", "2", "3");
    List<String> result = input.stream()
            .map(x -> x + " " + x)
            .filter(y -> !y.startsWith("1"))
            .collect(Collectors.toList());

Behind the scenes does it work like a) or b)

A

map
  "1" + " " + "1"
  "2" + " " + "2"
  "3" + " " + "3"
filter
  "1 1" does not begin with "1"? = false
  "2 2" does not begin with "1"? = true
  "3 3" does not begin with "1"? = true
collect
  add "2 2" to list
  add "3 3" to list
result = List("2 2", "3 3")

B

map
  "1" + " " + "1"
filter
  "1 1" does not begin with "1"? = false
map
  "2" + " " + "2"
filter
  "2 2" does not begin with "1"? = true
collect
  add "2 2" to list
map
  "3" + " " + "3"
filter
  "3 3" does not begin with "1"? = true
collect
  add "3 3" to list
result = List("2 2", "3 3")

Upvotes: 9

Views: 3984

Answers (2)

skiwi
skiwi

Reputation: 69259

It works like option B, not necessarilly in that exact order, but more on that it does every operation on one element at a time.

The reasoning behind this is that variables only pass the stream once, so you need to perform all actions when you have that element right now, because once the element has passed, it is gone forever (from the stream's point of view).

Your code is, in a linear setting, very very very roughly equivalent to the following code, this is a very simplified version, but I hope you get the idea:

Collection<String> input = Arrays.asList("1", "2", "3");
Function<String, String> mapper = x -> x + " " + x;
Predicate<String> filter = y -> !y.startsWith("1");
Collector<String, ?, List<String>> toList = Collectors.toList();

List<String> list = ((Supplier<List<String>>)toList.supplier()).get();
for (String in : input) {
    in = mapper.apply(in);
    if (filter.test(in)) {
        ((BiConsumer<List<String>, String>)toList.accumulator()).accept(list, in);
    }
}

What you see here, is:

  • As input a Collection<String>, your input.
  • A Function<String, String> matching your map().
  • A Predciate<String> matching your filter().
  • A Collector<String, ?, List<String>> matching your collect(), this is a collector that operates on elements of type String, uses intermediate storage ? and gives a List<String>.

What it then does is:

  • Obtain a new list, from the supplier (type: Supplier<List<String>>) of the collector.
  • Loop over every element of the input, done internally when operating on a Stream<String>, I am using a Collection<String> here for expliciteness such that we still have a connection to the old Java 7 world.
  • Apply your mapping function.
  • Test your filter predicate.
  • Obtain the accumulator (type: BiConsumer<List<String>, String>) of the toList collector, this is the binary consumer that takes as arguments the List<String> it already has, and the String it wants to add.
  • Feed our list and in to the accumulator.

Please take a very careful note that the real implementations is much much more advanced, as operations can happen in any order and multiple ones can happen, and much more.

Upvotes: 10

Rohit Jain
Rohit Jain

Reputation: 213233

One of the benefit of streams is lazy-evaluation of intermediate operations. That means, when the terminal operation, collect() in this case is executed, it asks for an element from previous intermediate operation - filter(), which in turns gets the element from map(), which in turns operates on first element from list.stream(). Same flow is followed for all the elements. So yes, the execution is more like option B.

Also, since the collector returned by Collectors.toList() is ordered, the elements are guaranteed to execute in order. In some cases, the evaluation might go out of order, when UNORDERED chararacteristic is set for a collector.

Upvotes: 5

Related Questions