CODEWITHSUNDEEP
phpmysqlnl2br
baltar bsg
baltar bsg

Reputation: 15

why isn't nl2br() working

I am trying to format $c (basically it is blocks of information that I need to appear in paragraph form). I am using nl2br() to introduce line breaks. So I have the following code:

   $search_output .= "*<i>$a</i>- <br/><b>field c: </b> $c <i>$b</i><br />";
 echo nl2br($c);

The problem is $c shows up twice. Once as unformatted in $search_output and then formatted in echo nl2br(), but it pops up at the very top of the page and messes up my layout.

I want to merge nl2br($c) into $search_output.

I tried this:

$search_output .= "*<i>$a</i>- <br/><b>field c: </b> nl2br($c) <i>$b</i><br />";

It doesn't work.

Please help. I am new at this. And losing my mind. nl2br() works separately, but I need the formatted content as part of $search_output.

Upvotes: 0

Views: 809

Answers (2)

Adrian Preuss
Adrian Preuss

Reputation: 3113

use the right syntax. Its an function/method and not an variable

 $search_output .= "*<i>$a</i>- <br/><b>field c: </b> " . nl2br($c) . " <i>$b</i><br />";

Upvotes: 0

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 798536

Stop the string, put the code, start the string again. And don't forget to concatenate.

$search_output .= "*<i>$a</i>- <br/><b>field c: </b> " . nl2br($c) . " <i>$b</i><br />";

Upvotes: 1

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