CODEWITHSUNDEEP
objective-cios7
Chaaruu Jadhav
Chaaruu Jadhav

Reputation: 484

validate alphanumeric value in UITextField

I want alphanumeric value in textfield.If user enter only character or number then sending massage.Even no special characters acceptable.

        NSString *str = askIdTxt.text;
        NSCharacterSet *alphanumericSet = [NSCharacterSet alphanumericCharacterSet];
        NSCharacterSet *numberSet = [NSCharacterSet decimalDigitCharacterSet];
        BOOL isAlphaNumericOnly = [[str stringByTrimmingCharactersInSet:alphanumericSet] isEqualToString:@""] && ! [[str stringByTrimmingCharactersInSet:numberSet] isEqualToString:@""];
        if (isAlphaNumericOnly) {
             NSLog(@"isAplhaNumericOnly: %@",(isAlphaNumericOnly? @"Yes":@"No"));
        }

This is always returning true. I am not getting what is wrong in this.

Upvotes: 5

Views: 3648

Answers (5)

Lukasz 'Severiaan' Grela
Lukasz 'Severiaan' Grela

Reputation: 6258

How about using regular expression:

-(BOOL)isAlphaNumericOnly:(NSString *)input 
{
    NSString *alphaNum = @"[a-zA-Z0-9]+";
    NSPredicate *regexTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", alphaNum];

    return [regexTest evaluateWithObject:input];
}

and then use it

if([self isAlphaNumeric:str])
{
    NSLog(@"IT IS ALPHA NUMERIC STRING");

}

edit The same technique can be used to validate passwords, you need only better regex:

-(BOOL)isPasswordStrong:(NSString *)password {
/*
8-20 chars
at least one letter
at least one number OR special character
no more than 3 repeated characters
*/
        NSString *strongPass= @"^(?!.*(.)\\1{3})((?=.*[\\d])(?=.*[A-Za-z])|(?=.*[^\\w\\d\\s])(?=.*[A-Za-z])).{8,20}$";;
        NSPredicate *regexTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", strongPass];

        return [regexTest evaluateWithObject:password];
}

using the regular expression you can create different rules but this can give you a headstart,

Upvotes: 6

Thukaram
Thukaram

Reputation: 1083

Try this 

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{

        NSCharacterSet *charactersToBlock = [[NSCharacterSet alphanumericCharacterSet] invertedSet];
        return ([string rangeOfCharacterFromSet:charactersToBlock].location == NSNotFound);
}

Upvotes: 1

NeverHopeless
NeverHopeless

Reputation: 11233

I guess the problem is in the alphanumericCharacterSet, here is a part from doc:

Informally, this set is the set of all characters used as basic units of alphabets, syllabaries, ideographs, and digits.

So, I am expecting it would allow the unwanted characters to you.

You may also try using Regex:

NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"^[a-z\\d]+$" options:NSRegularExpressionCaseInsensitive error:&error];
NSUInteger matches = [regex numberOfMatchesInString:str options:NSMatchingReportCompletion range:NSMakeRange(0, [str length])];

BOOL hasMatches = (matches > 0) && !error;

Upvotes: 2

Parvendra Singh
Parvendra Singh

Reputation: 985

 Call this Method and modify it accordingly .....


   -(BOOL) isPasswordValid:(NSString *)pwd 
     {

       if ( [pwd length]<4 || [pwd length]>20 ) return NO;  // too long or too short
       NSRange rang;
       rang = [pwd rangeOfCharacterFromSet:[NSCharacterSet letterCharacterSet]];
       if ( !rang.length ) return NO;  // no letter
       rang = [pwd rangeOfCharacterFromSet:[NSCharacterSet decimalDigitCharacterSet]];
       if ( !rang.length )  return NO;  // no number;
       return YES;

     }

Upvotes: 2

Mayur Prajapati - MeProgrammer
Mayur Prajapati - MeProgrammer

Reputation: 5602

Try this :

NSCharacterSet *blockedCharacters = [[[NSCharacterSet alphanumericCharacterSet] invertedSet] retain];

- (BOOL)textField:(UITextField *)field shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)characters
{
    return ([characters rangeOfCharacterFromSet:blockedCharacters].location == NSNotFound);
}

Upvotes: 0

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