CODEWITHSUNDEEP
phpinputfopen
Pierre Olivier Tran
Pierre Olivier Tran

Reputation: 1875

Numeric value is not a number?

I've just started learning PHP, i'm trying to get a numeric input by using fopen. The program should just ask user to type a number, and echo if the number is odd, even, or not a number. The thing is, no matter what I type, it is never considered as a number. Here's my code

#!/usr/bin/php
<?php

echo "Entrez un nombre: ";
$handle = fopen ("php://stdin","r");
$nbr = fgets($handle);
if (is_numeric($nbr))
{
    if ($nbr % 2 == 0)
        echo "Le chiffre $nbr est Pair\n";
    else if ($nbr % 2 == 1)
        echo "Le chiffre $nbr est Impair\n";
}
else
    echo "'$nbr' n'est pas un chiffre\n";
?>

At this point, I can type anything I want as an input, but the answer is always "'[what I typed] ' n'est pas un chiffre"

Upvotes: 2

Views: 344

Answers (1)

Yogu
Yogu

Reputation: 9445

fgets gets a line from the stream, including the trailing newline character. $nbr is thus "123\n", which is not numeric.

You can check this by printing strlen($nbr) (is 2) and then ord($nbr[1]) which prints 10 - the ASCII code for the newline character.

Use trim($nbr) to remove the newline character, and also additional whitespace before and after the input.

Upvotes: 2

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