CODEWITHSUNDEEP
c
Irrationnelle
Irrationnelle

Reputation: 33

I want to avoid 'floating point error' in C program

I would like to avoid 'floating point error in this code.

A purpose of this code is to gain 'The average of whole numbers' but the number of 'whole numbers' is limited by the input of users. Please help me.

#include <stdio.h>

int main(void)
{
    int num=0;
    int limit;
    int result=0;

    printf("number of integer: ");
    scanf("&d", &limit);

    while(num<limit)
    {
        int output;
        printf("Input integer : ");
        scanf("%d", &output);
        result += output;
        num++;
    }
    printf("average of total integer: %d \n", result/limit);
    return 0;
}

Thank you for reading.

Upvotes: 3

Views: 322

Answers (2)

OldSchool
OldSchool

Reputation: 2183

As the result of two integer dividing is also an integer,so it as

printf("average of total integer: %f \n", result/(float)limit);

when you type cast the variable limit to float what happens is that result will be implicitly converted to float and so the result is a float.

Upvotes: 1

Bartlomiej Lewandowski
Bartlomiej Lewandowski

Reputation: 11180

When you divide 2 integers, the result is also an integer.

To return a float, you need to cast one of the arguments as a float.

So your last line becomes

printf("average of total integer: %f \n", result/(float)limit);

Upvotes: 3

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