CODEWITHSUNDEEP
jqueryajax
Attila Naghi
Attila Naghi

Reputation: 2686

JQuery Interesting Issue

This is my piece of code :

.................
 remProduct: function(e, $a) {
        var orderObj = {
            pid:   $a.parents('li').find('input=[name=pid]').val(),
            pk_id: $a.parents('div.packet').attr('id') || $a.parents('div.section').attr('id'),
            isSideCart: !!$a.parents('div.packet').length
        };
        var callBack = function(json) {
            if (json.success) { 
                if ($("div.sidebar").length) {
                    $("div.sidebar").replaceWith(json.body)
                } else if ($("div.content").length) {
                    $("div.content").html(json.body);
                }
            }
            front.rebindSideCart();
        };
        $.post(this.getPath() + '/remove-product', orderObj, callBack, 'json');
    },
.................

The idea is that I add or remove product from my Package. When I add a product and after that I want to remove it , it doesn't work and the firebug show me this error:

Error: Syntax error, unrecognized expression: input=[name=pid]

, BUT if i refreshed the page it works. Can anyone explain me why ? Thx in advance !

Upvotes: 1

Views: 34

Answers (3)

Rohan Kumar
Rohan Kumar

Reputation: 40639

It should be input[name=pid] not input=[name=pid]

pid:   $a.parents('li').find('input[name=pid]').val(),
                   //--------------^ 
                   // remove = from this position as it is not a valid selector

Syntax:

$("element[attribute='value']")

For egs:

$("input[name='pid']")

Upvotes: 1

Felix
Felix

Reputation: 38102

You don't need to use = right after input inside input=[name=pid]:

pid: $a.parents('li').find('input[name=pid]').val(),

The correct syntax for Attribute Equals Selector is: jQuery("[attribute='value']").

Since your value is just a normal string then you don't need to wrap it inside double quotes, but if your value contain any of the meta-characters ( such as !"#$%&'()*+,./:;<=>?@[\]^{|}~` ) as a literal part of a name, then it must be escaped with with two backslashes: \\ or wrapped in quotes.

Upvotes: 1

Milind Anantwar
Milind Anantwar

Reputation: 82231

You dont need = operator after input.also wrap attribute value in quotes.it should be:

find('input[name="pid"]')

pid :

 pid:$a.parents('li').find('input[name="pid"]').val(),

Upvotes: 1

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