CODEWITHSUNDEEP
phparraysvar-dump
feedc0de
feedc0de

Reputation: 3796

Cant get value in PHP array but var_dump shows that it exists

Long time, my PHP-application ran on a linux server with apache and PHP.

Now I've set up a windows server with apache and php and simple PHP-Programs have problems.

var_dump($data);
die(var_dump($data['a']));

results in

object(stdClass)#1 (1) { ["a"]=> string(1) "b" } 
Fatal error: Cannot use object of type stdClass as array in BLUB.php on line 14

var_dump says there is an index a. Why does $data['a'] throw an exception?

EDIT: $data is json_decode($something);

Upvotes: 4

Views: 2099

Answers (5)

ponciste
ponciste

Reputation: 2229

since $data in an object you have to access it this way: 

$data->a;

Otherwise, you can typecast it to an array and access it actually like an array

$dataArr = (array) $data;

$dataArr['a'];

NOTE

This is possible only whether your object attributes are public

Upvotes: 0

Barif
Barif

Reputation: 1552

You should use:

 $data = json_decode($something, true);

To get array from json

Upvotes: 2

Ragdata
Ragdata

Reputation: 1186

The error contains your answer - $data is actually an object of type stdClass. You could either:

a) access the property 'a' with $data->a or b) typecast $data as an array using (array)$data

Upvotes: 3

user3477804
user3477804

Reputation:

As the error says $data is an object, not an array. As such, you want to use object access, rather than array access. In this case, that would be var_dump($data->a)

Upvotes: 2

Realitätsverlust
Realitätsverlust

Reputation: 3953

Because its an object, not an array. You cant access it like that. This would be correct:

$data->a;

Upvotes: 3

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