Ari
Reputation: 4191
Printing All Regex Matches
I'm using the perl/sed commands below to capture and print regex matches, unfortunately, both only print the first match in a line, rather than all matches. How can I modify either or both commands to print all matches? Grep and Awk alternative commands are welcome.
perl -nle 'print "$1" if /.*([0|1]\.[0-9]{0,2}).*/'
sed -rne "s/.*([0|1]\.[0-9]{0,2})/\1/p"
Upvotes: 1
Views: 1140
Answers (2)
Miller
Reputation: 35208
Just use while with the /g modifier to the regex instead of an if. Also need to get rid of your needless use of .* around the regex.
perl -nle 'print $1 while /([0|1]\.[0-9]{0,2})/g'
Finally, [0|1] should probably just be reduced to [01], unless you want to match a | before the period.
Upvotes: 5
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