CODEWITHSUNDEEP
javajakarta-eeosgideclarative-services
user3488102
user3488102

Reputation:

OSGi - get ds service by name (id)

I am newbie in OSGi. I have googled about a few hours but couldn't find the answer. Maybe my understanding is wrong. So the problem. Lets suppose I have a component.

<component name="sample.component" immediate="true">
  <implementation class="sample.SampleComparator" />
  <service>
    <provide interface="java.util.Comparator" />
  </service>
</component>

and in code:

ServiceReference[] serviceReferences = 
    bundleContext.getServiceReferences(
        java.util.Comparator.class.getName(), "(name=sample.component)");

But I get null. Where is the mistake? Is filter (name=sample.component) right? Or how can I set id of the service and lookup by it?

Upvotes: 3

Views: 932

Answers (1)

Balazs Zsoldos
Balazs Zsoldos

Reputation: 6046

The name of the service property is "component.name", not "name".

If you do this, it will work:

getServiceReferences(java.util.Comparator.class.getName(),"(component.name=sample.component)");

Upvotes: 6

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