CODEWITHSUNDEEP
java
nickmcneely7
nickmcneely7

Reputation: 49

The sum of all squares between 1 and 100 inclusive?

Doing an assignment for my computer science class and can't quite figure out what I'm doing wrong. I have to write a program that adds all the squares between 1 and 100 (1, 4, 9, 16, 25, 36, 49, 64, 81, 100) As part of the assignment I'm required to use a "while" statement, so no "for" statements will help. My current code is as follows.

import java.util.Scanner;

public class While42B {
    public static void main(String []args ) {
        Scanner reader = new Scanner(System.in);
        int n = 1;
        int sum = 0;
        while (n <= 100) {
            n = (n*n);
            n++;

            sum = (sum + n); 
        }
        System.out.println(sum);
    }
}

And the return I get from the GUI is

710

Any help would be greatly appreciated, thank you!

Upvotes: 3

Views: 39608

Answers (6)

Nicholas John Grabill
Nicholas John Grabill

Reputation: 1

Simply read the mathematics and then proceed to translate the mathematical operations into code. I've worked out the mathematics which I hope could help you. I have also provided an answer to the question stated by your professor, I do hope that I am able to have been helpful in your arrangements. No credit needed except to Carl Friedrich Gauss.

X(nsquared base 1 + nsquared base n) divided by 2

X equals number of numbers (100) and n base 1 equals first number (1) and n base n equals last number (100), I did not include the squares in the numerical description but you do need too include squares in the first and last number. 1 squared and 100 squared.

  • Do these operations according too PEMDAS ( order of operations ).
  • I don't have a high enough reputation so I can't post photos, sorry for that, I hope this all helped though.
  • The answer is (500,050)

Upvotes: -1

Ashraful Haque
Ashraful Haque

Reputation: 559

If you want to do it in your way I mean first square the value of each number,keep it in a variable and add it to the sum you can use a different variable instead of n to store the square value of each number like this :

int n = 1;
int squareValue;
int sum = 0;
while (n <= 10) {

    squareValue= (n*n);

    sum += squareValue; 

    n++;
}
System.out.println(sum);

Upvotes: 4

peter.petrov
peter.petrov

Reputation: 39437

I realize you're looking for a while loop but
just FYI you can use the direct formula:

System.out.println( n * (n + 1) * (2 * n + 1) / 6);

Upvotes: 9

Aman Agnihotri
Aman Agnihotri

Reputation: 3023

Just as an add-on, in Java 8, one can do the sum of squares of first 10 natural numbers as follows:

int sum = IntStream.rangeClosed(1, 10).map(n -> n * n).sum();

Upvotes: 5

nanofarad
nanofarad

Reputation: 41271

Look at this statement:

n = (n*n);

You're squaring n inside the loop, and then incrementing it. Do the following instead:

while (n <= 10) {
    sum = (sum + (n*n)); 
    n++;
}

This way, you don't modify n by squaring it, and you can properly track its value for the while loop.

Upvotes: 13

CMPS
CMPS

Reputation: 7769

You are changing the value of n in: n= n*n So now you are not looping from 1 to 100, you are skipping a lot of numbers

Upvotes: 3

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