CODEWITHSUNDEEP
javaregexstringsubstringsplit
Niz
Niz

Reputation: 15

Split the string at various index position

I am trying to solve this in Java. I have a long string of information and I want to split the string based on the length of the fields given.

Example: `FirstNameLastName yy-mm-dd549Eastwolframstreet

I have a list of fields given along with its length. There are n number of fields. example fields:

If the name is less than 9 characters spaces occupy the remaining positions. i.e Lastname is length 9 but there are only 8 letters remaining one is a space.

What is the best way to extract those fields from each of its given length?

Upvotes: 0

Views: 118

Answers (2)

newuser
newuser

Reputation: 8466

Try this,

    String value = "FirstNameLastName yy-mm-ddAddress                       FirstNameLastName yy-mm-ddAddress                       FirstNameLastName yy-mm-ddAddress                       ";

    for (int i = 0; i < value.length(); i++)
    {
        System.out.println("First Name : "+value.substring(i, i + 9));
        System.out.println("Last Name : "+value.substring((i + 9), i + 18));
        System.out.println("Date : "+value.substring(i + 18, i + 26));
        System.out.println("Address : "+value.substring(i + 26, i + 56));
        i = i + 55;
    }

Upvotes: 1

aliteralmind
aliteralmind

Reputation: 20163

Knowing that each part is an exact length--and if it happens to be less, it's padded by spaces--this is a perfect situation for using String.substring(i,i) and String.trim().

For example: str.substring(0, 9) is the first nine characters. Now trim it, and any extra pad-spaces will be eliminated.

Upvotes: 1

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